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# square root doubt

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Senior Manager
Joined: 29 Jan 2011
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20 Sep 2011, 02:25
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(x^2 )(y^2 )(z^2) = 80

then will xyz be +/- \sqrt{80} ?? or just +\sqrt{80}??
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Joined: 20 Dec 2010
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20 Sep 2011, 03:03
siddhans wrote:
(x^2 )(y^2 )(z^2) = 80

then will xyz be +/- \sqrt{80} ?? or just +\sqrt{80}??

$$(xyz)^2=80$$

$$xyz=\pm \sqrt{80}$$
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Re: square root doubt   [#permalink] 20 Sep 2011, 03:03
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