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# subset query !

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Manager
Joined: 02 Jun 2011
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29 Jun 2011, 04:51
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kindly explain...

to form subset of ( 10, 14, 17, 24 ) containing an odd element , istn't it ok to take 4p1 ? which gives answer as 4.

please guide on probability. i am realy week on this probability.permutation and combination !!!
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29 Jun 2011, 04:57
Could you please post the full question ?
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29 Jun 2011, 05:06
how many different subset of the set (10, 14, 17, 24) contain an odd umer of elements?
a.) 3
b.) 4
c.) 8
d.) 10
e.) 12

pls help!
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29 Jun 2011, 05:13
kashishh wrote:
how many different subset of the set (10, 14, 17, 24) contain an odd number of elements?
a.) 3
b.) 4
c.) 8
d.) 10
e.) 12

pls help!

{10}
{14}
{17}
{24}
{10,14,17}
{10,14,24}
{10,17,24}
{14,17,24}

$$C^{4}_{1}+C^{4}_{3}=8$$

Ans: "C"
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29 Jun 2011, 05:17
4C1 + 4C3 = 4 + 4 = 8

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29 Jun 2011, 05:17
doesn't this quest mean 17 as odd element ?
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29 Jun 2011, 05:19
how should i get through probabilty questions? i am not able to make any improvement ... any read to recommend?
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29 Jun 2011, 05:22
Ans 1 - This question means that, if you select the elements of the set in all possible ways, how many of them would comprise odd numbers. So you can select 0,1,2,3,4 elements at a time. fluke has shown how many combinations are there for 1 and 3 elements.
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29 Jun 2011, 05:23
Ans 2 - Read the Permutations and Combinations + Probability chapters in GMAT Math Book.

math-combinatorics-87345.html

math-probability-87244.html
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29 Jun 2011, 05:27
thanks to you both !!
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29 Jun 2011, 15:44
odd number of elements.

As we have 4 elements , to form odd number of elements we can either form 1 element sets or 3 element sets.

so total possibilities = 4c1+4c3 = 4 +4 =8

Re: subset query !   [#permalink] 29 Jun 2011, 15:44
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