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# Sue's monthly earnings consist of a monthly salary and a 4

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Sue's monthly earnings consist of a monthly salary and a 4 [#permalink]

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05 Jun 2008, 12:11
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Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of \$2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were \$3,620 in July and \$3,580 in August.
(2) Sue's monthly salary was \$3,500 in July and in August.

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Director
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Re: Sue's salary [#permalink]

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05 Jun 2008, 18:03
Wow, another C trap, 2 days in row.

\$40 is 4% of an amount, so Sue sold \$1000 more merchandise in July than in August.

A is my answer

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Re: Sue's salary [#permalink]

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05 Jun 2008, 18:59
yeah i think its A as well

we know from the stem that their montly salaries are the same, so the only difference must be due to the difference in sales ....

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Re: Sue's salary [#permalink]

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05 Jun 2008, 23:28
I go with A
Let monthly salary = x+0.04(y-2000) where x=monthly salary and y= monthly sales
taking equation (1) 3620=x+0.04(y1-2000) &3580=x+0.04(y2-2000)
{since monthly salary is the same)
above equation can be solved to give y1-y2.........SUFFICIENT

taking (2) monthly salary is same so cant say anything abt sales..........INSUFICIENT

Whts the OA?

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Re: Sue's salary [#permalink]

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05 Jun 2008, 23:50
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of \$2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were \$3,620 in July and \$3,580 in August.
(2) Sue's monthly salary was \$3,500 in July and in August.

A.

3620 - 3580 = 40 , 40 =( Total_sale - 2000)* 4/100 total sale was greater than 1000\$

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Re: Sue's salary [#permalink]

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06 Jun 2008, 02:50
For (1), what if Sue sold nothing in July ?

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Re: Sue's salary [#permalink]

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06 Jun 2008, 04:48
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of \$2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were \$3,620 in July and \$3,580 in August.
(2) Sue's monthly salary was \$3,500 in July and in August.

IMO A is the answer

pretty good question though coz C seems to be the easier choice here
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Re: Sue's salary [#permalink]

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06 Jun 2008, 09:23
kevincan wrote:
For (1), what if Sue sold nothing in July ?

If that is the case, then the statement in the stem "Sue's monthly salary was the same in July as in August" is inaccurate, so the question is flawed, and E is then the answer.

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Re: Sue's salary [#permalink]

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06 Jun 2008, 10:21
Good Question...got me...good practice...Thanks kevincan.

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Re: Sue's salary [#permalink]

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06 Jun 2008, 10:28
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of \$2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were \$3,620 in July and \$3,580 in August.
(2) Sue's monthly salary was \$3,500 in July and in August.

X+.04(Y-2000)

1:

X+.04(J-2000)=3620

X+.04(A-2000)=3580

--> 4J/100-80+X=3620 --> 370000=4J+100X -->

J=-25X+92500
A=-25X+91500

J-A = 1000

2: Insuff.

A

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Re: Sue's salary [#permalink]

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06 Jun 2008, 10:37
Impressive GMATBLACKBELT

GMATBLACKBELT wrote:
kevincan wrote:
Sue's monthly earnings consist of a monthly salary and a 4 percent commission on the portion of her monthly sales that is in excess of \$2,000. If Sue's monthly salary was the same in July as in August, how much greater were her sales in July than in August?

(1) Sue's monthly earnings were \$3,620 in July and \$3,580 in August.
(2) Sue's monthly salary was \$3,500 in July and in August.

X+.04(Y-2000)

1:

X+.04(J-2000)=3620

X+.04(A-2000)=3580

--> 4J/100-80+X=3620 --> 370000=4J+100X -->

J=-25X+92500
A=-25X+91500

J-A = 1000

2: Insuff.

A

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Re: Sue's salary [#permalink]

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06 Jun 2008, 13:12
kevincan wrote:
For (1), what if Sue sold nothing in July ?

I don't think that (1) is sufficient, for we don't know her monthly salary. For all we know, it is \$3,580 and she sold nothing in August. Then her commission in July, \$40, would have been 4% of x - 2,000, where x is her July sales (i.e. \$3,000)

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Re: Sue's salary [#permalink]

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06 Jun 2008, 13:21
kevincan wrote:
kevincan wrote:
For (1), what if Sue sold nothing in July ?

I don't think that (1) is sufficient, for we don't know her monthly salary. For all we know, it is \$3,580 and she sold nothing in August. Then her commission in July, \$40, would have been 4% of x - 2,000, where x is her July sales (i.e. \$3,000)

That's true, but \$40 is 4% of \$1000.

No matter how you look at it, you'll find that the difference is \$1,000.
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Re: Sue's salary [#permalink]

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06 Jun 2008, 13:26
Imagine that her salary were \$3,580 and she had sold \$1,500 in August. What would her income be? And she had sold \$3,000?

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Re: Sue's salary [#permalink]

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06 Jun 2008, 13:32
kevincan wrote:
Imagine that her salary were \$3,580 and she had sold \$1,500 in August. What would her income be? And she had sold \$3,000?

If, in August, her income was \$3,580 and she sold \$1,500, then her base salary is \$3,580 because her sales must be over \$2000 in order for her to earn 4% of those sales.

Don't focus on the base salary. Instead, focus on the difference of \$40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her \$40 more, then we have the equation of .04x = 40. The answer is \$1000. No matter what you make the base salary, the difference in commission is always going to be \$40.

HOWEVER....I do see your point. If she sold nothing, she would get the same base salary. Then the next month, in order for her to earn \$40 more than her base salary, she has to sell \$3,000 (\$1,000 more than the 2,000) because x - 2000 * .04 = \$40. X here has to be \$3,000. The difference would be \$3,000, not \$1,000.

Good point kevincan, this is not an air-tight question.

The question really should state that she sold at least \$2,000 every month. Then sales of \$0 would not be possible and we would know that \$1,000 had to be the answer and #1 was sufficient, but without that information, it truly is insufficient.

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Re: Sue's salary [#permalink]

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06 Jun 2008, 13:38
jallenmorris wrote:
kevincan wrote:
Imagine that her salary were \$3,580 and she had sold \$1,500 in August. What would her income be? And she had sold \$3,000?

If, in August, her income was \$3,580 and she sold \$1,500, then her base salary is \$3,580 because her sales must be over \$2000 in order for her to earn 4% of those sales. That is right

Don't focus on the base salary. Instead, focus on the difference of \$40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her \$40 more, then we have the equation of .04x = 40. The answer is \$1000. No matter what you make the base salary, the difference in commission is always going to be \$40.

Do you agree that in order to have monthly earnings of \$3,620 in July, her sales have had to be \$3000 ? Remember that the first \$2,000 of sales don't have an impact on her monthly earnings.

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Re: Sue's salary [#permalink]

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06 Jun 2008, 13:42
jallenmorris wrote:
kevincan wrote:
Imagine that her salary were \$3,580 and she had sold \$1,500 in August. What would her income be? And she had sold \$3,000?

If, in August, her income was \$3,580 and she sold \$1,500, then her base salary is \$3,580 because her sales must be over \$2000 in order for her to earn 4% of those sales.

Don't focus on the base salary. Instead, focus on the difference of \$40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her \$40 more, then we have the equation of .04x = 40. The answer is \$1000. No matter what you make the base salary, the difference in commission is always going to be \$40.

HOWEVER....I do see your point. If she sold nothing, she would get the same base salary. Then the next month, in order for her to earn \$40 more than her base salary, she has to sell \$3,000 (\$1,000 more than the 2,000) because x - 2000 * .04 = \$40. X here has to be \$3,000. The difference would be \$3,000, not \$1,000.

Good point kevincan, this is not an air-tight question.

The question really should state that she sold at least \$2,000 every month. Then sales of \$0 would not be possible and we would know that \$1,000 had to be the answer and #1 was sufficient, but without that information, it truly is insufficient.

Perhaps the question was testing our ability to consider the possiblilty that her base salary was \$3,580. I don't see the question as flawed

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Re: Sue's salary [#permalink]

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06 Jun 2008, 13:44
Maybe it is flawed, but we're not sure yet because you've not posted the OA.

kevincan wrote:
jallenmorris wrote:
kevincan wrote:
Imagine that her salary were \$3,580 and she had sold \$1,500 in August. What would her income be? And she had sold \$3,000?

If, in August, her income was \$3,580 and she sold \$1,500, then her base salary is \$3,580 because her sales must be over \$2000 in order for her to earn 4% of those sales.

Don't focus on the base salary. Instead, focus on the difference of \$40.

You know that she earns the same base salary from month to month, so the difference has to come from the sales commission of 4%. If she earns 4% of some number (x) and that gets her \$40 more, then we have the equation of .04x = 40. The answer is \$1000. No matter what you make the base salary, the difference in commission is always going to be \$40.

HOWEVER....I do see your point. If she sold nothing, she would get the same base salary. Then the next month, in order for her to earn \$40 more than her base salary, she has to sell \$3,000 (\$1,000 more than the 2,000) because x - 2000 * .04 = \$40. X here has to be \$3,000. The difference would be \$3,000, not \$1,000.

Good point kevincan, this is not an air-tight question.

The question really should state that she sold at least \$2,000 every month. Then sales of \$0 would not be possible and we would know that \$1,000 had to be the answer and #1 was sufficient, but without that information, it truly is insufficient.

Perhaps the question was testing our ability to consider the possiblilty that her base salary was \$3,580. I don't see the question as flawed

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Re: Sue's salary [#permalink]

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07 Jun 2008, 02:47
wow. I also thought the answer was A.
But after reading your posts, i should say, it should be C because:
- problem asks for the difference in sales. - and without giving base salary nor sales for each month, we have to account for so many other possibilities (all positive integers less than 2000)
Great post

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Re: Sue's salary [#permalink]

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07 Jun 2008, 21:39
There is no need 2 know her salary as its the same 4 all the months, so we can just cancel it out frm the toal. We r intersted in the differewcne in sales ,that we can find out by the equations.
kevincan wrote:
kevincan wrote:
For (1), what if Sue sold nothing in July ?

I don't think that (1) is sufficient, for we don't know her monthly salary. For all we know, it is \$3,580 and she sold nothing in August. Then her commission in July, \$40, would have been 4% of x - 2,000, where x is her July sales (i.e. \$3,000)

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Re: Sue's salary   [#permalink] 07 Jun 2008, 21:39

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# Sue's monthly earnings consist of a monthly salary and a 4

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