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# Sum of two numbers

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Manager
Joined: 28 Jan 2004
Posts: 202

Kudos [?]: 28 [0], given: 4

Location: India

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12 Jun 2009, 12:37
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If two digit integer M and N are positive and have same digits but in reverse order which of the following can not be the sum of M and N.
a). 181
b). 165
c). 121
d). 99
e). 44

Kudos [?]: 28 [0], given: 4

Director
Joined: 03 Jun 2009
Posts: 782

Kudos [?]: 902 [1], given: 56

Location: New Delhi
WE 1: 5.5 yrs in IT
Re: Sum of two numbers [#permalink]

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12 Jun 2009, 12:42
1
KUDOS
Let M = 10x+y (where x is tens digit and y is units digit)
N = 10y+x

M+N=10x+y+10y+x = 11(x+y)

This means that the sum would be divisible by 11.

We have been asked, which of the given option cannot be possible. So its 181 only, as all other nos are divisible by 11.

_________________

Kudos [?]: 902 [1], given: 56

Intern
Joined: 04 Mar 2008
Posts: 42

Kudos [?]: 3 [0], given: 6

Re: Sum of two numbers [#permalink]

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12 Jun 2009, 14:11
it has to be multiple of 11. and A is not. Hence, answer is A.

Kudos [?]: 3 [0], given: 6

Re: Sum of two numbers   [#permalink] 12 Jun 2009, 14:11
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