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# Superbowl

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Director
Joined: 07 Jun 2004
Posts: 612
Location: PA
Followers: 7

Kudos [?]: 792 [0], given: 22

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06 Feb 2011, 06:56
00:00

Difficulty:

25% (medium)

Question Stats:

68% (01:27) correct 32% (01:25) wrong based on 19 sessions

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A Superbowl sponsor X has a 30 sec commerical that is part of the 15 different commercials the network will show in the first commercial break .

What is the probability that Company X's advertisement will be one of the first two be shown during the first commercial break?

(A) 1/ 225
(B) 1 / 30
(C) 1 /15
(D) 2 / 15
(E) 4 /15
[Reveal] Spoiler: OA

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If the Q jogged your mind do Kudos me : )

Math Forum Moderator
Joined: 20 Dec 2010
Posts: 2013
Followers: 163

Kudos [?]: 1822 [0], given: 376

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06 Feb 2011, 07:14

For X's ad to be shown as one of the first two ads:

It can be shown as the first ad
or
Doesn't get shown as the first ad AND gets shown as the second ad

$$P= \frac{1}{15}+\frac{14}{15}*\frac{1}{14}$$
$$P= \frac{1}{15}+\frac{1}{15}$$
$$P= \frac{2}{15}$$

"The information that it is a 30 sec ad is superfluous."

Ans: "D"
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Manager
Joined: 27 Oct 2010
Posts: 185
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Kudos [?]: 10 [0], given: 20

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06 Feb 2011, 11:25
1/15 + (14/15) * 1/14 = 2/15 D
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7368
Location: Pune, India
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Kudos [?]: 15079 [0], given: 224

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07 Feb 2011, 21:17
rxs0005 wrote:
A Superbowl sponsor X has a 30 sec commerical that is part of the 15 different commercials the network will show in the first commercial break .

What is the probability that Company X's advertisement will be one of the first two be shown during the first commercial break?

(A) 1/ 225
(B) 1 / 30
(C) 1 /15
(D) 2 / 15
(E) 4 /15

Or you can simply view it as 2 favorable spots (1st or 2nd) out of 15 available ones so probability = 2/15
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Re: Superbowl   [#permalink] 07 Feb 2011, 21:17
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