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Manager  G
Joined: 24 Feb 2020
Posts: 165
Location: Italy
WE: Analyst (Investment Banking)
Suppose that x will be randomly selected from the set:  [#permalink]

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1 00:00

Difficulty:   35% (medium)

Question Stats: 73% (02:02) correct 27% (03:11) wrong based on 15 sessions

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Suppose that x will be randomly selected from the set:

{–3/2, –1, –1/2, 0, 5/2}

and that y will be randomly selected from the set

{–3/4, –1/4, 2, 11/4}.

What is the probability that x/y < 0 ?

A. 1/100
B. 1/20
C. 3/20
D. 1/3
E. 2/5
Math Expert V
Joined: 02 Sep 2009
Posts: 64249
Re: Suppose that x will be randomly selected from the set:  [#permalink]

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Ravixxx wrote:
Suppose that x will be randomly selected from the set:

{–3/2, –1, –1/2, 0, 5/2}

and that y will be randomly selected from the set

{–3/4, –1/4, 2, 11/4}.

What is the probability that x/y < 0 ?

A. 1/100
B. 1/20
C. 3/20
D. 1/3
E. 2/5

x/y to be negative x and y must have different signs.

P(x is negative and y is positive) = 3/5*1/2
P(x is positive and y is negative) = 1/5*1/2

Sum = 3/5*1/2 + 1/5*1/2 = 2/5.

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DS Forum Moderator V
Joined: 19 Oct 2018
Posts: 1853
Location: India
Re: Suppose that x will be randomly selected from the set:  [#permalink]

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Total number of ways to choose (x,y) = 5*4= 20

If x/y<0, then

Case 1 - x>0 and y<0

Number of ways to choose (x,y) = 1*2 = 2

Case 2 - x<0 and y>0

Number of ways to choose (x,y) = 3*2 = 6

The probability that x/y < 0= (2+6)/20 = 2/5

Ravixxx wrote:
Suppose that x will be randomly selected from the set:

{–3/2, –1, –1/2, 0, 5/2}

and that y will be randomly selected from the set

{–3/4, –1/4, 2, 11/4}.

What is the probability that x/y < 0 ?

A. 1/100
B. 1/20
C. 3/20
D. 1/3
E. 2/5 Re: Suppose that x will be randomly selected from the set:   [#permalink] 02 Apr 2020, 11:17

# Suppose that x will be randomly selected from the set:  