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Susan drove an average speed of 30 miles per hour for the [#permalink]

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02 Nov 2010, 06:56

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Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. If she made no stops during the trip, what was Susan's average speed, in miles per hour, for the entire trip?

a. 35 b. 40 c. 45 d. 50 e. 55

The Common Formula is Average speed = Total distance / Total time. However if the distances traveled with two different speeds are the same (as 30 in this case), we can calculate the average speed as per following rule. ratio of two distinct speeds = 1:2 Difference of two distinct speeds = 60 - 30 = 30 Now divide this difference by the sum of intergers of ratio (i.e. by 1+2 = 3 in this case ) 30/3 = 10 Average speed will be 10 X 1 part away from the lower speed i.e. 30 + 10 X 1 = 40.

The benefit of this method is once practiced enough you can calculate the average speed mentally or with minimal calculation and thereby can save valuable time on the GMAT

Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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30 Jul 2013, 16:45

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Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

What we have here are equal distances for both segments.

First segment: 30 miles/hour and covered 30 miles, therefore it took one hour. Second segment: 60 miles/hour and covered 30 miles, therefore it took 1/2 hour.

(Total distance / total time) (60 / [1hr+ 1/2hr]) (60 / 1.5) = 40 miles avg. speed.

A. 35 B. 40 C. 45 D. 50 E. 55

(B)

When don't we simply add the distances/speeds together to get the average?

Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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10 Feb 2016, 21:17

Narenn wrote:

jsphcal wrote:

Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. If she made no stops during the trip, what was Susan's average speed, in miles per hour, for the entire trip?

a. 35 b. 40 c. 45 d. 50 e. 55

The Common Formula is Average speed = Total distance / Total time. However if the distances traveled with two different speeds are the same (as 30 in this case), we can calculate the average speed as per following rule. ratio of two distinct speeds = 1:2 Difference of two distinct speeds = 60 - 30 = 30 Now divide this difference by the sum of intergers of ratio (i.e. by 1+2 = 3 in this case ) 30/3 = 10 Average speed will be 10 X 1 part away from the lower speed i.e. 30 + 10 X 1 = 40.

The benefit of this method is once practiced enough you can calculate the average speed mentally or with minimal calculation and thereby can save valuable time on the GMAT

Regards,

Abhijit

Nice method, but why should it be 10 away from the lower speed and not from the higher speed?

Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35 B. 40 C. 45 D. 50 E. 55

We are given that Susan drove at an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. We must determine her average speed overall. The formula for average speed is:

average speed = total distance/total time

For the first half of the trip, we know that Susan’s speed was 30 mph and her distance was 30 miles, so her time was 30/30 = 1 hour.

For the second half of the trip, we know that Susan’s speed was 60 mph and her distance was 30 miles, so her time was 30/60 = 1/2 hour. Therefore her average speed in miles per hour is:

average speed = (30 + 30)/(1 + ½)

average speed = 60/(3/2)

average speed = 40

Answer: B
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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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11 May 2017, 05:03

Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35 B. 40 C. 45 D. 50 E. 55

Sol: Average Speed = Total Distance/Total time Total Distance = 30 miles + 30 miles = 60 miles Total time = Time taken for the 1st 30 miles + time taken for the next 30 miles = (30miles/30mph) + (30 miles/60 mph) = (1 + 0.5) hours = 1.5 hours

Average speed = Total Distance/Total time = 60/1.5 = 40 mph The answer is (B).
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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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11 May 2017, 05:12

anilnandyala wrote:

Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35 B. 40 C. 45 D. 50 E. 55

Time taken in travelling 1st 30 miles = 30/30 = 1 hr Time taken in travelling remaining 30 miles = 30/60 = 1/2 hr Total distance traveled = 30+30 = 60 miles Total time taken = 1+1/2 = 3/2 hr Average speed = \(\frac{60}{(3/2)}\) = 40 miles/hr
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