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Susan drove an average speed of 30 miles per hour for the

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Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35
B. 40
C. 45
D. 50
E. 55
[Reveal] Spoiler: OA

Last edited by Bunuel on 13 Oct 2013, 03:01, edited 1 time in total.
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Re: susan drove an average speed [#permalink]

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anilnandyala wrote:
susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

a 35
b 40
c 45
d 50
e 55


\(average \ speed=\frac{total \ distance \ covered}{total \ time}\);

Total distance covered = 30 + 30 = 60 miles;
Total time = 30/30 + 30/60 = 3/2 hours;

\(average \ speed=\frac{total \ distance \ covered}{total \ time}=\frac{60}{\frac{3}{2}}=40\).

Answer: B.
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Re: Susan drove an average speed of 30 mph for the first 30 min [#permalink]

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New post 19 Mar 2013, 22:05
Your reasoning is correct. Probably the answer is incorrect unless you have not changed either the question or the answer.
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Re: Susan drove an average speed of 30 mph for the first 30 min [#permalink]

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New post 19 Mar 2013, 22:51
Avg. speed = total distance / total time

Total distance = 60 miles
Total time = 30 / 30 + 30/60 = 3/2

Avg. speed = 40.

Answer - B
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Re: Susan drove an average speed of 30 mph for the first 30 min [#permalink]

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jsphcal wrote:
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. If she made no stops during the trip, what was Susan's average speed, in miles per hour, for the entire trip?

a. 35
b. 40
c. 45
d. 50
e. 55


The Common Formula is Average speed = Total distance / Total time.
However if the distances traveled with two different speeds are the same (as 30 in this case), we can calculate the average speed as per following rule.
ratio of two distinct speeds = 1:2
Difference of two distinct speeds = 60 - 30 = 30
Now divide this difference by the sum of intergers of ratio (i.e. by 1+2 = 3 in this case ) 30/3 = 10
Average speed will be 10 X 1 part away from the lower speed i.e. 30 + 10 X 1 = 40.

The benefit of this method is once practiced enough you can calculate the average speed mentally or with minimal calculation and thereby can save valuable time on the GMAT

Regards,

Abhijit
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Last edited by Narenn on 20 Mar 2013, 04:56, edited 1 time in total.

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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 25 Mar 2013, 11:40
My approach:

30/30 -> 1h
30/60 -> 0.5h
---------1.5h total and then 60/1.5 -> 40 (1.5 -> 3 -> 4.5 -> 6)
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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

What we have here are equal distances for both segments.

First segment: 30 miles/hour and covered 30 miles, therefore it took one hour.
Second segment: 60 miles/hour and covered 30 miles, therefore it took 1/2 hour.

(Total distance / total time)
(60 / [1hr+ 1/2hr])
(60 / 1.5) = 40 miles avg. speed.

A. 35
B. 40
C. 45
D. 50
E. 55

(B)

When don't we simply add the distances/speeds together to get the average?

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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 03 Feb 2015, 16:58
Rate x Time = Distance
Going: 30 x 1 = 30
Returning: 30 x .5 = 30

Avg speed = Total distance/Total Time
=(30+30)/ (1+.5)
=40

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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 10 Feb 2016, 21:17
Narenn wrote:
jsphcal wrote:
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. If she made no stops during the trip, what was Susan's average speed, in miles per hour, for the entire trip?

a. 35
b. 40
c. 45
d. 50
e. 55


The Common Formula is Average speed = Total distance / Total time.
However if the distances traveled with two different speeds are the same (as 30 in this case), we can calculate the average speed as per following rule.
ratio of two distinct speeds = 1:2
Difference of two distinct speeds = 60 - 30 = 30
Now divide this difference by the sum of intergers of ratio (i.e. by 1+2 = 3 in this case ) 30/3 = 10
Average speed will be 10 X 1 part away from the lower speed i.e. 30 + 10 X 1 = 40.

The benefit of this method is once practiced enough you can calculate the average speed mentally or with minimal calculation and thereby can save valuable time on the GMAT

Regards,

Abhijit



Nice method, but why should it be 10 away from the lower speed and not from the higher speed?

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Why can't we get her average speed by weighting her speed by the proportion of the total distance realized at a certain speed?

e.g. why is 30(30/60)+60(30/60)=15+30 incorrect?

Thank you please let me know if i haven't been clear enough

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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 24 Feb 2017, 11:02
Hi Bunuel,

I don't know if this approach is right. I got the answer though

distance = speed x time
60 = (30 + 60) x time
60 = 90 x time
60/90 = time
2/3 multiplied by 60 = 40

Therefore, the answer is B. Is my approach correct?

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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 25 Feb 2017, 00:08
matthewsmith_89 wrote:
Hi Bunuel,

I don't know if this approach is right. I got the answer though

distance = speed x time
60 = (30 + 60) x time
60 = 90 x time
60/90 = time
2/3 multiplied by 60 = 40

Therefore, the answer is B. Is my approach correct?


No, that;'s not correct.


Distance = Average Speed * Time.

Distance = 60;
Time = 30/30 + 30/60 = 3/2 hours;

60 = Average Speed * 3/2

Average Speed = 40.
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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 27 Feb 2017, 12:13
anilnandyala wrote:
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35
B. 40
C. 45
D. 50
E. 55


We are given that Susan drove at an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles per hour for the remaining 30 miles of the trip. We must determine her average speed overall. The formula for average speed is:

average speed = total distance/total time

For the first half of the trip, we know that Susan’s speed was 30 mph and her distance was 30 miles, so her time was 30/30 = 1 hour.

For the second half of the trip, we know that Susan’s speed was 60 mph and her distance was 30 miles, so her time was 30/60 = 1/2 hour. Therefore her average speed in miles per hour is:

average speed = (30 + 30)/(1 + ½)

average speed = 60/(3/2)

average speed = 40

Answer: B
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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 18 Mar 2017, 20:30
30 miles/ Hour speed for 30 miles => Time Takem = 1 Hr.
60 miles/Hour Speed for remaining 30 miles => Time taken = 0.5 Hour.

Avg Speed = 60/(1+0.5) = 40 mph.

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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 11 May 2017, 05:03
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35
B. 40
C. 45
D. 50
E. 55

Sol: Average Speed = Total Distance/Total time
Total Distance = 30 miles + 30 miles = 60 miles
Total time = Time taken for the 1st 30 miles + time taken for the next 30 miles
= (30miles/30mph) + (30 miles/60 mph)
= (1 + 0.5) hours
= 1.5 hours

Average speed = Total Distance/Total time = 60/1.5 = 40 mph
The answer is (B).
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Re: Susan drove an average speed of 30 miles per hour for the [#permalink]

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New post 11 May 2017, 05:12
anilnandyala wrote:
Susan drove an average speed of 30 miles per hour for the first 30 miles of a trip & then at a average speed of 60 miles/hr for the remaining 30 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip

A. 35
B. 40
C. 45
D. 50
E. 55


Time taken in travelling 1st 30 miles = 30/30 = 1 hr
Time taken in travelling remaining 30 miles = 30/60 = 1/2 hr
Total distance traveled = 30+30 = 60 miles
Total time taken = 1+1/2 = 3/2 hr
Average speed = \(\frac{60}{(3/2)}\) = 40 miles/hr
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Re: Susan drove an average speed of 30 miles per hour for the   [#permalink] 11 May 2017, 05:12
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