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Test 3, Question 14

Author Message
Current Student
Joined: 16 Jan 2009
Posts: 186

Kudos [?]: 52 [0], given: 62

Location: Ithaca, New York
Schools: Cornell University - The Johnson School

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27 Oct 2009, 04:41
I'm sorry I couldn't find this question when I search for it.

Quote:
Is G < K ?

1. G > K^2
2. G and K are positive integers

* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

Statement (1) by itself is insufficient. Consider the following two examples which satisfy S1 but can't prove that G < K:

G=1/10, K=1/10 and G=1/3 , K=1/2

Statement (2) by itself is insufficient. We know nothing about the values of G and K.

Statements (1) and (2) combined are sufficient. For G > K^2 > 1 to be true, G > K.

I don't get this question. I chose E. I cannot reconcile this statement in the answer explanation "For G > K^2 > 1 to be true, G > K". I say not necessarily. I can disprove that statement by using the info up above G < K if G=1/3 and K=1/2. So it's possible that G=1/3 and K=1/4 which means G > K and satisfies both statements while using G=1/3 and K=1/2 means that G < K and this satisfies both statements. It can go either way, resulting in a "maybe" to the original question. Am I missing something here?

Kudos [?]: 52 [0], given: 62

CIO
Joined: 02 Oct 2007
Posts: 1216

Kudos [?]: 987 [1], given: 334

Re: Test 3, Question 14 [#permalink]

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27 Oct 2009, 04:47
1
KUDOS
It seems like you missed that $$G$$ and $$K$$ are integers according to S2 .
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Kudos [?]: 987 [1], given: 334

Current Student
Joined: 16 Jan 2009
Posts: 186

Kudos [?]: 52 [0], given: 62

Location: Ithaca, New York
Schools: Cornell University - The Johnson School
Re: Test 3, Question 14 [#permalink]

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27 Oct 2009, 04:56
dzyubam wrote:
It seems like you missed that $$G$$ and $$K$$ are integers according to S2 .

Haha! Yes I did. Thanks! Tricky little bugger.

Kudos [?]: 52 [0], given: 62

Re: Test 3, Question 14   [#permalink] 27 Oct 2009, 04:56
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Test 3, Question 14

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