The above graph lists the monthly sales (in $100,000 increments) at a

Total sales in Jan = 2 units
Total number of agents in Jan =2
Sales per Agent in Jan = 2/2 = 1 unit

Total sales in June = 8 units
Total number of agents in June = 4
Sales per Agent in June = 8/4 = 2 unit

% Increase = [(Final Value - Initial value)/Initial Value]*100

i.e. % increase = [(2 - 1) / 1]*100 = 100%

Answer: Option B

Sales in Jan=$200,000
No of agents in Jan=2
Sales per agent=$100,000
Sales in June=$800,000
No of agents in June=4
Sales per agent in June=$200,000
Reqd % increase=(200,000-100,000/100,000)*100=100%
Answer B

800score Official Solution:

(B) In January, the dealership had 2 agents and had sales of $200,000, or $100,000 per agent. An agent was added to the sales force in March (making 3) and then one more was added in May (making 4). This leaves 4 agents on the sales force for June, when the dealership sold $800,000 or $200,000 per agent ($800,000/4). We can find the percent difference by dividing the difference between the two per-agent amounts by the per-agent amount in January:
Percent Difference = ($200,000 – $100,000) / ($100,000)= 100,000 ÷ 100,000 = 1 or 100%. The correct answer is choice (B).

The trap answer is choice (D). $200,000 per agent is double $100,000 per agent. But remember that the question asks for the percent increase. $200,000 represents 200% of $100,000, but only 100% more than $100,000.

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