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# The above graph lists the monthly sales (in \$100,000 increments) at a

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Math Expert
Joined: 02 Sep 2009
Posts: 59712
The above graph lists the monthly sales (in \$100,000 increments) at a  [#permalink]

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10 Jul 2015, 02:34
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Difficulty:

25% (medium)

Question Stats:

79% (01:39) correct 21% (01:40) wrong based on 169 sessions

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The above graph lists the monthly sales (in \$100,000 increments) at a car dealership. For January and February, the dealership had two sales agents. The dealership added a sales agent in March and one more in May. What was the percent increase in sales per agent in June compared to January?

A. 50%
B. 100%
C. 125%
D. 200%
E. 400%

Kudos for a correct solution.

Attachment:

diagram.gif [ 4.01 KiB | Viewed 4095 times ]

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Re: The above graph lists the monthly sales (in \$100,000 increments) at a  [#permalink]

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10 Jul 2015, 04:24
Bunuel wrote:

The above graph lists the monthly sales (in \$100,000 increments) at a car dealership. For January and February, the dealership had two sales agents. The dealership added a sales agent in March and one more in May. What was the percent increase in sales per agent in June compared to January?

A. 50%
B. 100%
C. 125%
D. 200%
E. 400%

Kudos for a correct solution.

Attachment:
diagram.gif

Total number of agents in Jan =2
Total number of agents in June = 4

Total sales in Jan = 2 'units'
Total sales in June = 8 'units'

Thus PER AGENT, % increase = [(8/4)-(2/2)] /(2/2) *100 = 100% increase. Thus B is the correct answer.
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Joined: 26 Dec 2011
Posts: 115
Schools: HBS '18, IIMA
Re: The above graph lists the monthly sales (in \$100,000 increments) at a  [#permalink]

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10 Jul 2015, 06:09
1
Bunuel wrote:

The above graph lists the monthly sales (in \$100,000 increments) at a car dealership. For January and February, the dealership had two sales agents. The dealership added a sales agent in March and one more in May. What was the percent increase in sales per agent in June compared to January?

A. 50%
B. 100%
C. 125%
D. 200%
E. 400%

Kudos for a correct solution.

Attachment:
diagram.gif

In January, the dealership has 2 agents and sales of \$200,000, or \$100,000 per agent.
After adding two more agents, 4 agents on the sales force for June and sales of \$800,000 or \$200,000 per agent (\$800,000/4).

Percent Difference = (\$200,000 – \$100,000) / (\$100,000)= 1 or 100%.
ANS B
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Re: The above graph lists the monthly sales (in \$100,000 increments) at a  [#permalink]

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10 Jul 2015, 06:50
Bunuel wrote:

The above graph lists the monthly sales (in \$100,000 increments) at a car dealership. For January and February, the dealership had two sales agents. The dealership added a sales agent in March and one more in May. What was the percent increase in sales per agent in June compared to January?

A. 50%
B. 100%
C. 125%
D. 200%
E. 400%

Kudos for a correct solution.

Attachment:
diagram.gif

Total sales in Jan = 2 units
Total number of agents in Jan =2
Sales per Agent in Jan = 2/2 = 1 unit

Total sales in June = 8 units
Total number of agents in June = 4
Sales per Agent in June = 8/4 = 2 unit

% Increase = [(Final Value - Initial value)/Initial Value]*100

i.e. % increase = [(2 - 1) / 1]*100 = 100%

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Posts: 633
Re: The above graph lists the monthly sales (in \$100,000 increments) at a  [#permalink]

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11 Jul 2015, 10:47
Bunuel wrote:

The above graph lists the monthly sales (in \$100,000 increments) at a car dealership. For January and February, the dealership had two sales agents. The dealership added a sales agent in March and one more in May. What was the percent increase in sales per agent in June compared to January?

A. 50%
B. 100%
C. 125%
D. 200%
E. 400%

Kudos for a correct solution.

Attachment:
diagram.gif

Sales in Jan=\$200,000
No of agents in Jan=2
Sales per agent=\$100,000
Sales in June=\$800,000
No of agents in June=4
Sales per agent in June=\$200,000
Reqd % increase=(200,000-100,000/100,000)*100=100%
Math Expert
Joined: 02 Sep 2009
Posts: 59712
Re: The above graph lists the monthly sales (in \$100,000 increments) at a  [#permalink]

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13 Jul 2015, 02:52
Bunuel wrote:

The above graph lists the monthly sales (in \$100,000 increments) at a car dealership. For January and February, the dealership had two sales agents. The dealership added a sales agent in March and one more in May. What was the percent increase in sales per agent in June compared to January?

A. 50%
B. 100%
C. 125%
D. 200%
E. 400%

Kudos for a correct solution.

Attachment:
diagram.gif

800score Official Solution:

(B) In January, the dealership had 2 agents and had sales of \$200,000, or \$100,000 per agent. An agent was added to the sales force in March (making 3) and then one more was added in May (making 4). This leaves 4 agents on the sales force for June, when the dealership sold \$800,000 or \$200,000 per agent (\$800,000/4). We can find the percent difference by dividing the difference between the two per-agent amounts by the per-agent amount in January:
Percent Difference = (\$200,000 – \$100,000) / (\$100,000)= 100,000 ÷ 100,000 = 1 or 100%. The correct answer is choice (B).

The trap answer is choice (D). \$200,000 per agent is double \$100,000 per agent. But remember that the question asks for the percent increase. \$200,000 represents 200% of \$100,000, but only 100% more than \$100,000.
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Re: The above graph lists the monthly sales (in \$100,000 increments) at a   [#permalink] 13 Jul 2015, 02:52
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