Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 28 Apr 2012
Posts: 16

The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
18 Dec 2012, 01:33
2
This post received KUDOS
13
This post was BOOKMARKED
Question Stats:
69% (02:55) correct
31% (01:52) wrong based on 301 sessions
HideShow timer Statistics
The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were $1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive? A. $x B. $3x C. $4x D. $5x E $14x
Official Answer and Stats are available only to registered users. Register/ Login.
Last edited by Bunuel on 18 Dec 2012, 02:28, edited 1 time in total.
Renamed the topic.



Math Expert
Joined: 02 Sep 2009
Posts: 39744

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
18 Dec 2012, 02:33
3
This post received KUDOS
Expert's post
3
This post was BOOKMARKED
dcastan2 wrote: The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were $1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive?
A. $x B. $3x C. $4x D. $5x E $14x Pick some smart number for \(x\), let \(x=2\) (I chose \(x=2\) as in this case monthly shipments would be \(\frac{x}{2}=1\)). From January to April, inclusive \(4x=8\) brooms were produced and in May the company paid for storage of 81=7 brooms, in next month for storage of 6 and so on. So the total storage cost would be: \(1*(7+6+5+4+3+2+1+0)=28\) > as \(x=2\), then \(28=14x\). Answer: E. Identical question from GMAT Prep to practice: acertainbusinessproducedxrakeseachmonthformnovember101738.html
_________________
New to the Math Forum? Please read this: All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



Manager
Joined: 02 Sep 2012
Posts: 248
Location: United States
Concentration: Entrepreneurship, Finance
GMAT Date: 07252013
GPA: 3.83
WE: Architecture (Computer Hardware)

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
20 Dec 2012, 11:04
In this case if x=4 then how the equation will turn out to be can you please explain
_________________
"Giving kudos" is a decent way to say "Thanks" and motivate contributors. Please use them, it won't cost you anything



Manager
Joined: 24 Mar 2010
Posts: 80

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
20 Dec 2012, 11:36
1
This post received KUDOS
January  April : 4 months , so 4x brooms produced. From May its an A.P. with a = 3.5x (since we are counting from May 2nd, so 0.5x has already been sold on May 1st) d =  0.5 x So 8th Term (December ) is  a + 7d = 0 Sum of AP is (first term + last term) * n/2 = 3.5x * 8 / 2 = 14x Hence E
_________________
 Stay Hungry, stay Foolish 



Math Expert
Joined: 02 Sep 2009
Posts: 39744

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
21 Dec 2012, 03:50



Manager
Joined: 02 Sep 2012
Posts: 248
Location: United States
Concentration: Entrepreneurship, Finance
GMAT Date: 07252013
GPA: 3.83
WE: Architecture (Computer Hardware)

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
21 Dec 2012, 04:12
your reply helped me a lot in understanding this question. Are there any 700 + level questions on geomenrty??
_________________
"Giving kudos" is a decent way to say "Thanks" and motivate contributors. Please use them, it won't cost you anything



Math Expert
Joined: 02 Sep 2009
Posts: 39744

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
21 Dec 2012, 04:20



Senior Manager
Joined: 08 Apr 2012
Posts: 453

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
23 Nov 2013, 06:29
Bunuel wrote: dcastan2 wrote: The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were $1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive?
A. $x B. $3x C. $4x D. $5x E $14x Pick some smart number for \(x\), let \(x=2\) (I chose \(x=2\) as in this case monthly shipments would be \(\frac{x}{2}=1\)). From January to April, inclusive \(4x=8\) brooms were produced and in May the company paid for storage of 81=7 brooms, in next month for storage of 6 and so on. So the total storage cost would be: \(1*(7+6+5+4+3+2+1+0)=28\) > as \(x=2\), then \(28=14x\). Answer: E. Identical question from GMAT Prep to practice: acertainbusinessproducedxrakeseachmonthformnovember101738.htmlHi Bunuel, Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically. Thanks



Manager
Joined: 25 Oct 2013
Posts: 169

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
23 Nov 2013, 11:14
1
This post received KUDOS
ronr34 wrote: Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically. Thanks Hello ron We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us \(4x\) brooms in inventory by end of April. On first of each month from May to December \(\frac{x}{2}\) brooms are sold. Therefore we will have \(4x\frac{x}{2} = \frac{7x}{2}\) brooms on May 2nd > storage cost is $1 per broom per month so in may the company pays \(\frac{7x}{2}\) Similarly we have \(\frac{7x}{2}\frac{x}{2} = \frac{6x}{2}\) brooms on June 2 > storage cost is \(\frac{6x}{2}\). July 2nd \(\frac{5x}{2}\) Continuing this we have \(\frac{x}{2}\) brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get \(\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x\) Hope this helps!
_________________
Click on Kudos if you liked the post!
Practice makes Perfect.



Senior Manager
Joined: 08 Apr 2012
Posts: 453

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
23 Nov 2013, 13:15
gmatprav wrote: ronr34 wrote: Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically. Thanks Hello ron We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us \(4x\) brooms in inventory by end of April. On first of each month from May to December \(\frac{x}{2}\) brooms are sold. Therefore we will have \(4x\frac{x}{2} = \frac{7x}{2}\) brooms on May 2nd > storage cost is $1 per broom per month so in may the company pays \(\frac{7x}{2}\) Similarly we have \(\frac{7x}{2}\frac{x}{2} = \frac{6x}{2}\) brooms on June 2 > storage cost is \(\frac{6x}{2}\). July 2nd \(\frac{5x}{2}\) Continuing this we have \(\frac{x}{2}\) brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get \(\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x\) Hope this helps! I was able to do this calculation but I am looking for a general formula for cases like this.... Is there anything of the sort?



Manager
Joined: 25 Oct 2013
Posts: 169

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
24 Nov 2013, 06:58
ronr34 wrote: gmatprav wrote: ronr34 wrote: Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically.
Hello ron We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us \(4x\) brooms in inventory by end of April. On first of each month from May to December \(\frac{x}{2}\) brooms are sold. Therefore we will have \(4x\frac{x}{2} = \frac{7x}{2}\) brooms on May 2nd > storage cost is $1 per broom per month so in may the company pays \(\frac{7x}{2}\) Similarly we have \(\frac{7x}{2}\frac{x}{2} = \frac{6x}{2}\) brooms on June 2 > storage cost is \(\frac{6x}{2}\). July 2nd \(\frac{5x}{2}\) Continuing this we have \(\frac{x}{2}\) brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get \(\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x\) Hope this helps! I was able to do this calculation but I am looking for a general formula for cases like this.... Is there anything of the sort? This problem is not a generic problem that warrants a formula. If you solved it like this then you are on right track. You mentioned how to do it without plugging in numbers Note that I did not plug in numbers. We can create a formula for similar problems, but in the end it will be harder to remember the formula than to solve it directly.
_________________
Click on Kudos if you liked the post!
Practice makes Perfect.



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1857
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
04 Apr 2014, 00:49
gmatprav wrote: ronr34 wrote: Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically. Thanks Hello ron We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us \(4x\) brooms in inventory by end of April. On first of each month from May to December \(\frac{x}{2}\) brooms are sold. Therefore we will have \(4x\frac{x}{2} = \frac{7x}{2}\) brooms on May 2nd > storage cost is $1 per broom per month so in may the company pays \(\frac{7x}{2}\) Similarly we have \(\frac{7x}{2}\frac{x}{2} = \frac{6x}{2}\) brooms on June 2 > storage cost is \(\frac{6x}{2}\). July 2nd \(\frac{5x}{2}\) Continuing this we have \(\frac{x}{2}\) brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get \(\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x\) Hope this helps! Did in the same way ; with just a addition Wrote \(4x = \frac{8x}{2}\) for the simplicity of calculation & proceeded As denominator is same, just add the numerator & then divide by 2 Addition of 1 to 7; used formula \(\frac{n(n+1)}{2} = 7 * \frac{8}{2} = 28\) Dividing by 2 28/2 = 14
_________________
Kindly press "+1 Kudos" to appreciate



GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16022

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
17 Jul 2015, 07:56
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources



GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16022

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
25 Jul 2016, 04:05
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources



CEO
Joined: 17 Jul 2014
Posts: 2525
Location: United States (IL)
Concentration: Finance, Economics
GPA: 3.92
WE: General Management (Transportation)

Re: The ACME company manufactured x brooms per month from Januar [#permalink]
Show Tags
16 Nov 2016, 09:54
1
This post received KUDOS
dcastan2 wrote: The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were $1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive?
A. $x B. $3x C. $4x D. $5x E $14x first, let's see how many x were manufactured. January X February X March X April X total manufactured: 4x May 1st sold 0.5x = remained till end of the month 3.5x  paid 3.5x for storage June 1st sold 0.5x = remained till end of the month 3x  paid 3x for storage July 1st sold 0.5x = remained till end of the month 2.5x  paid 2.5x for storage August 1st sold 0.5x = remained till end of the month 2x  paid 2x for storage September 1st sold 0.5x = remained till end of the month 1.5x  paid 1.5x for storage October 1st sold 0.5x = remained till end of the month 1x  paid 1x for storage November 1st sold 0.5x = remained till end of the month 0.5x  paid 0.5x for storage December 1st sold 0.5x = remained till end of the month 0x  paid 0. so total paid: 3.5x + 3x + 2.5x + 2x + 1.5x + 1x + 0.5x 3.5x + 2.5x = 6x 3x + 2x + 1x = 6x 1.5x + 0.5x = 2x 6x+6x+2x=14x answer is E.




Re: The ACME company manufactured x brooms per month from Januar
[#permalink]
16 Nov 2016, 09:54







