GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Oct 2019, 04:57

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# The ACME company manufactured x brooms per month from Januar

Author Message
TAGS:

### Hide Tags

Intern
Joined: 28 Apr 2012
Posts: 14
The ACME company manufactured x brooms per month from Januar  [#permalink]

### Show Tags

Updated on: 10 Dec 2017, 09:51
6
24
00:00

Difficulty:

55% (hard)

Question Stats:

71% (03:06) correct 29% (02:57) wrong based on 336 sessions

### HideShow timer Statistics

The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were $1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive? A.$x
B. $3x C.$4x
D. $5x E.$14x

Originally posted by dcastan2 on 18 Dec 2012, 01:33.
Last edited by Bunuel on 10 Dec 2017, 09:51, edited 2 times in total.
Renamed the topic.
Math Expert
Joined: 02 Sep 2009
Posts: 58390
Re: The ACME company manufactured x brooms per month from Januar  [#permalink]

### Show Tags

18 Dec 2012, 02:33
6
3
dcastan2 wrote:
The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were $1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive? A.$x
B. $3x C.$4x
D. $5x E$14x

Pick some smart number for $$x$$, let $$x=2$$ (I chose $$x=2$$ as in this case monthly shipments would be $$\frac{x}{2}=1$$).

From January to April, inclusive $$4x=8$$ brooms were produced and in May the company paid for storage of 8-1=7 brooms, in next month for storage of 6 and so on.

So the total storage cost would be: $$1*(7+6+5+4+3+2+1+0)=28$$ --> as $$x=2$$, then $$28=14x$$.

Identical question from GMAT Prep to practice: a-certain-business-produced-x-rakes-each-month-form-november-101738.html
_________________
Manager
Joined: 25 Oct 2013
Posts: 142
Re: The ACME company manufactured x brooms per month from Januar  [#permalink]

### Show Tags

23 Nov 2013, 11:14
4
1
ronr34 wrote:
Can you please post an algebraic solution to this problem?
I solved it plugging numbers, but I can't seem to do so algebraically.
Thanks

Hello ron

We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us $$4x$$ brooms in inventory by end of April. On first of each month from May to December $$\frac{x}{2}$$ brooms are sold. Therefore we will have

$$4x-\frac{x}{2} = \frac{7x}{2}$$ brooms on May 2nd ---> storage cost is $1 per broom per month so in may the company pays $$\frac{7x}{2}$$ Similarly we have $$\frac{7x}{2}-\frac{x}{2} = \frac{6x}{2}$$ brooms on June 2 ---> storage cost is $$\frac{6x}{2}$$. July 2nd $$\frac{5x}{2}$$ Continuing this we have $$\frac{x}{2}$$ brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get $$\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x$$ Hope this helps! _________________ Click on Kudos if you liked the post! Practice makes Perfect. ##### General Discussion Manager Joined: 02 Sep 2012 Posts: 188 Location: United States Concentration: Entrepreneurship, Finance GMAT Date: 07-25-2013 GPA: 3.83 WE: Architecture (Computer Hardware) Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 20 Dec 2012, 11:04 In this case if x=4 then how the equation will turn out to be can you please explain Manager Joined: 24 Mar 2010 Posts: 58 Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 20 Dec 2012, 11:36 2 1 January - April : 4 months , so 4x brooms produced. From May its an A.P. with a = 3.5x (since we are counting from May 2nd, so 0.5x has already been sold on May 1st) d = - 0.5 x So 8th Term (December ) is - a + 7d = 0 Sum of AP is (first term + last term) * n/2 = 3.5x * 8 / 2 = 14x Hence E _________________ - Stay Hungry, stay Foolish - Math Expert Joined: 02 Sep 2009 Posts: 58390 Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 21 Dec 2012, 03:50 2 skamal7 wrote: In this case if x=4 then how the equation will turn out to be can you please explain Sure. Say $$x=4$$, in this case monthly shipments would be $$\frac{x}{2}=2$$. Then from January to April, inclusive $$4x=16$$ brooms were produced and in May the company paid for storage of 16-2=14 brooms, in next month for storage of 12 and so on. So the total storage cost would be: $$1*(14+12+10+8+6+4+2+0)=56$$ --> as $$x=4$$, then $$56=14x$$. Answer: E. _________________ Manager Joined: 02 Sep 2012 Posts: 188 Location: United States Concentration: Entrepreneurship, Finance GMAT Date: 07-25-2013 GPA: 3.83 WE: Architecture (Computer Hardware) Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 21 Dec 2012, 04:12 your reply helped me a lot in understanding this question. Are there any 700 + level questions on geomenrty?? Math Expert Joined: 02 Sep 2009 Posts: 58390 Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 21 Dec 2012, 04:20 2 skamal7 wrote: your reply helped me a lot in understanding this question. Are there any 700 + level questions on geomenrty?? Check here: ds-question-directory-by-topic-difficulty-128728.html (DS) and here: gmat-ps-question-directory-by-topic-difficulty-127957.html (PS). Hope it helps. _________________ Senior Manager Joined: 08 Apr 2012 Posts: 327 Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 23 Nov 2013, 06:29 Bunuel wrote: dcastan2 wrote: The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were$1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive?

A. $x B.$3x
C. $4x D.$5x
E $14x Pick some smart number for $$x$$, let $$x=2$$ (I chose $$x=2$$ as in this case monthly shipments would be $$\frac{x}{2}=1$$). From January to April, inclusive $$4x=8$$ brooms were produced and in May the company paid for storage of 8-1=7 brooms, in next month for storage of 6 and so on. So the total storage cost would be: $$1*(7+6+5+4+3+2+1+0)=28$$ --> as $$x=2$$, then $$28=14x$$. Answer: E. Identical question from GMAT Prep to practice: a-certain-business-produced-x-rakes-each-month-form-november-101738.html Hi Bunuel, Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically. Thanks Senior Manager Joined: 08 Apr 2012 Posts: 327 Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 23 Nov 2013, 13:15 gmatprav wrote: ronr34 wrote: Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically. Thanks Hello ron We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us $$4x$$ brooms in inventory by end of April. On first of each month from May to December $$\frac{x}{2}$$ brooms are sold. Therefore we will have $$4x-\frac{x}{2} = \frac{7x}{2}$$ brooms on May 2nd ---> storage cost is$1 per broom per month so in may the company pays $$\frac{7x}{2}$$
Similarly we have $$\frac{7x}{2}-\frac{x}{2} = \frac{6x}{2}$$ brooms on June 2 ---> storage cost is $$\frac{6x}{2}$$.
July 2nd $$\frac{5x}{2}$$
Continuing this we have $$\frac{x}{2}$$ brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get

$$\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x$$

Hope this helps!

I was able to do this calculation but I am looking for a general formula for cases like this....
Is there anything of the sort?
Manager
Joined: 25 Oct 2013
Posts: 142
Re: The ACME company manufactured x brooms per month from Januar  [#permalink]

### Show Tags

24 Nov 2013, 06:58
ronr34 wrote:
gmatprav wrote:
ronr34 wrote:
Can you please post an algebraic solution to this problem?
I solved it plugging numbers, but I can't seem to do so algebraically.

Hello ron

We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us $$4x$$ brooms in inventory by end of April. On first of each month from May to December $$\frac{x}{2}$$ brooms are sold. Therefore we will have

$$4x-\frac{x}{2} = \frac{7x}{2}$$ brooms on May 2nd ---> storage cost is $1 per broom per month so in may the company pays $$\frac{7x}{2}$$ Similarly we have $$\frac{7x}{2}-\frac{x}{2} = \frac{6x}{2}$$ brooms on June 2 ---> storage cost is $$\frac{6x}{2}$$. July 2nd $$\frac{5x}{2}$$ Continuing this we have $$\frac{x}{2}$$ brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get $$\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x$$ Hope this helps! I was able to do this calculation but I am looking for a general formula for cases like this.... Is there anything of the sort? This problem is not a generic problem that warrants a formula. If you solved it like this then you are on right track. You mentioned how to do it without plugging in numbers Note that I did not plug in numbers. We can create a formula for similar problems, but in the end it will be harder to remember the formula than to solve it directly. _________________ Click on Kudos if you liked the post! Practice makes Perfect. SVP Status: The Best Or Nothing Joined: 27 Dec 2012 Posts: 1749 Location: India Concentration: General Management, Technology WE: Information Technology (Computer Software) Re: The ACME company manufactured x brooms per month from Januar [#permalink] ### Show Tags 04 Apr 2014, 00:49 gmatprav wrote: ronr34 wrote: Can you please post an algebraic solution to this problem? I solved it plugging numbers, but I can't seem to do so algebraically. Thanks Hello ron We are given that on 1st of each month x brooms are made from Jan to Apr. that gives us $$4x$$ brooms in inventory by end of April. On first of each month from May to December $$\frac{x}{2}$$ brooms are sold. Therefore we will have $$4x-\frac{x}{2} = \frac{7x}{2}$$ brooms on May 2nd ---> storage cost is$1 per broom per month so in may the company pays $$\frac{7x}{2}$$
Similarly we have $$\frac{7x}{2}-\frac{x}{2} = \frac{6x}{2}$$ brooms on June 2 ---> storage cost is $$\frac{6x}{2}$$.
July 2nd $$\frac{5x}{2}$$
Continuing this we have $$\frac{x}{2}$$ brooms left by Nov 2nd which are sold on Dec 1st, so no more brooms are left on Dec 2nd and no storage costs in december. By adding storage costs as derived above we get

$$\frac{7x}{2}+\frac{6x}{2}+\frac{5x}{2}+\frac{4x}{2}+\frac{3x}{2}+\frac{2x}{2}+\frac{x}{2} = \frac{28x}{2} = 14x$$

Hope this helps!

Did in the same way ; with just a addition

Wrote $$4x = \frac{8x}{2}$$ for the simplicity of calculation & proceeded

As denominator is same, just add the numerator & then divide by 2

Addition of 1 to 7; used formula $$\frac{n(n+1)}{2} = 7 * \frac{8}{2} = 28$$

Dividing by 2

28/2 = 14
_________________
Kindly press "+1 Kudos" to appreciate
Board of Directors
Joined: 17 Jul 2014
Posts: 2513
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
WE: General Management (Transportation)
Re: The ACME company manufactured x brooms per month from Januar  [#permalink]

### Show Tags

16 Nov 2016, 09:54
1
dcastan2 wrote:
The ACME company manufactured x brooms per month from January to April, inclusive. On the first of each month, during the following May to December, inclusive, it sold x/2 brooms. At the beginning of production on January 1st, the ACME company had no brooms in its inventory. If storage costs were $1 per month per broom, approximately how much, in terms of x, did the ACME company pay for storage from May 2nd to December 31st, inclusive? A.$x
B. $3x C.$4x
D. $5x E$14x

first, let's see how many x were manufactured.
January X
February X
March X
April X
total manufactured: 4x
May 1st sold 0.5x = remained till end of the month 3.5x - paid 3.5x for storage
June 1st sold 0.5x = remained till end of the month 3x - paid 3x for storage
July 1st sold 0.5x = remained till end of the month 2.5x - paid 2.5x for storage
August 1st sold 0.5x = remained till end of the month 2x - paid 2x for storage
September 1st sold 0.5x = remained till end of the month 1.5x - paid 1.5x for storage
October 1st sold 0.5x = remained till end of the month 1x - paid 1x for storage
November 1st sold 0.5x = remained till end of the month 0.5x - paid 0.5x for storage
December 1st sold 0.5x = remained till end of the month 0x - paid 0.

so total paid:
3.5x + 3x + 2.5x + 2x + 1.5x + 1x + 0.5x
3.5x + 2.5x = 6x
3x + 2x + 1x = 6x
1.5x + 0.5x = 2x

6x+6x+2x=14x

Manager
Status: Single
Joined: 02 Jan 2016
Posts: 174
Location: India
Concentration: General Management, Accounting
GMAT 1: 730 Q49 V40
GPA: 4
WE: Law (Manufacturing)
Re: The ACME company manufactured x brooms per month from Januar  [#permalink]

### Show Tags

04 Sep 2019, 03:39
1
Best way to do is not calculating, see the differences in the answer values.
At may itself the cost would be 4x, so it makes sense the answer will be higher than 5x, so 14 only
Re: The ACME company manufactured x brooms per month from Januar   [#permalink] 04 Sep 2019, 03:39
Display posts from previous: Sort by