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The area of a square is A = s2, where s is the length of one of the

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New post 16 Mar 2019, 22:53
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The area of a square is A =\(s^2\), where s is the length of one of the four equal sides. If the area of a square is quadrupled, by what factor has the length of any one of the sides been changed?

A)\(\sqrt{2}\)
B)2
C)\(2\sqrt{2}\)
D)4
E)\(\sqrt{6}\)

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Re: The area of a square is A = s2, where s is the length of one of the  [#permalink]

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New post 17 Mar 2019, 10:19
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\(4s^2 = (2s)^2\). Thus correct answer is B.
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The area of a square is A = s2, where s is the length of one of the  [#permalink]

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New post 27 Mar 2019, 04:48
Abhi077 wrote:
The area of a square is A =\(s^2\), where s is the length of one of the four equal sides. If the area of a square is quadrupled, by what factor has the length of any one of the sides been changed?

A)\(\sqrt{2}\)
B)2
C)\(2\sqrt{2}\)
D)4
E)\(\sqrt{6}\)



Pick an easy number Lets say, area is 25 then each side is 5.
Now area is made 4 times (quadrupled ) then Area becomes 100
If area is 100 then each side is 10
So each side of a square has been multiplied by a factor of 2.
Answer =B
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The area of a square is A = s2, where s is the length of one of the   [#permalink] 27 Mar 2019, 04:48
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