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The area of a square is A = s2, where s is the length of one of the

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The area of a square is A = s2, where s is the length of one of the  [#permalink]

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16 Mar 2019, 21:53
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The area of a square is A =$$s^2$$, where s is the length of one of the four equal sides. If the area of a square is quadrupled, by what factor has the length of any one of the sides been changed?

A)$$\sqrt{2}$$
B)2
C)$$2\sqrt{2}$$
D)4
E)$$\sqrt{6}$$

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Re: The area of a square is A = s2, where s is the length of one of the  [#permalink]

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17 Mar 2019, 09:19
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$$4s^2 = (2s)^2$$. Thus correct answer is B.
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The area of a square is A = s2, where s is the length of one of the  [#permalink]

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27 Mar 2019, 03:48
Abhi077 wrote:
The area of a square is A =$$s^2$$, where s is the length of one of the four equal sides. If the area of a square is quadrupled, by what factor has the length of any one of the sides been changed?

A)$$\sqrt{2}$$
B)2
C)$$2\sqrt{2}$$
D)4
E)$$\sqrt{6}$$

Pick an easy number Lets say, area is 25 then each side is 5.
Now area is made 4 times (quadrupled ) then Area becomes 100
If area is 100 then each side is 10
So each side of a square has been multiplied by a factor of 2.
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The area of a square is A = s2, where s is the length of one of the   [#permalink] 27 Mar 2019, 03:48