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The areas of three unshaded triangles are = T + 6T + 4T = 11T (half of a rectangle with area of 2 + half of a rectangle with area of 12 + half of a rectangle with area of 8).

Re: The area of each of the 16 square regions in the figure abov [#permalink]

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07 Mar 2014, 07:43

Bunuel.. can you please elaborate on "The areas of three unshaded triangles are = T + 6T + 4T = 11T (half of a rectangle with area of 2 + half of a rectangle with area of 12 + half of a rectangle with area of 8)." I not able to follow this part.

Re: The area of each of the 16 square regions in the figure abov [#permalink]

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07 Mar 2014, 17:58

Option B. Let T be any convenient no. say 36. Side of each smaller square=6 Side of bigger square=6*4=24 Area shaded=24^2-(area of 3 unshaded right triangles) =576-36-144-216 =180 Which is 5*36 Ans:5T

Bunuel.. can you please elaborate on "The areas of three unshaded triangles are = T + 6T + 4T = 11T (half of a rectangle with area of 2 + half of a rectangle with area of 12 + half of a rectangle with area of 8)." I not able to follow this part.

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The areas of three unshaded triangles are = Half of the area of blue rectangle with area of 2T , thus T; Half of the area of black rectangle with area of 8T , thus 4T. Half of the area of red rectangle with area of 12T , thus 6T.

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Re: The area of each of the 16 square regions in the figure abov [#permalink]

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