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The area of the circumscribed circle in the figure above is 32π. What

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Bunuel
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The area of the circumscribed circle in the figure above is 32π. What [#permalink] New post   23 Aug 2018, 04:00
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The area of the circumscribed circle in the figure above is 32π. What is the area of the square?


A. \(\frac{8\sqrt{2}}{\pi}\)

B. \(\frac{32}{\pi}\)

C. \(\frac{64}{\pi}\)

D. 32

E. 64


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PKN
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Re: The area of the circumscribed circle in the figure above is 32π. What [#permalink] New post   23 Aug 2018, 04:13
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Bunuel wrote:
The area of the circumscribed circle in the figure above is 32π. What is the area of the square?


A. \(\frac{8\sqrt{2}}{\pi}\)

B. \(\frac{32}{\pi}\)

C. \(\frac{64}{\pi}\)

D. 32

E. 64


Hi Bunuel,
Kindly affix diagram.
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Bunuel
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Re: The area of the circumscribed circle in the figure above is 32π. What [#permalink] New post   23 Aug 2018, 04:20
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PKN wrote:
Bunuel wrote:
The area of the circumscribed circle in the figure above is 32π. What is the area of the square?


A. \(\frac{8\sqrt{2}}{\pi}\)

B. \(\frac{32}{\pi}\)

C. \(\frac{64}{\pi}\)

D. 32

E. 64


Hi Bunuel,
Kindly affix diagram.

______________
Done. Thank you.
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Re: The area of the circumscribed circle in the figure above is 32π. What [#permalink] New post   23 Aug 2018, 04:27
Bunuel wrote:

The area of the circumscribed circle in the figure above is 32π. What is the area of the square?


A. \(\frac{8\sqrt{2}}{\pi}\)

B. \(\frac{32}{\pi}\)

C. \(\frac{64}{\pi}\)

D. 32

E. 64


Show Spoiler
Attachment:
image009 (1).jpg


Given area of circle=32π
Or, πr^2=32π
Or, \(r=4\sqrt{2}\)

Diagonal of square=diameter of circle=2r=8\sqrt{2}
Or, \(\sqrt{2}\)* side length of square=\(8\sqrt{2}\)
Or, side length of square=8

So, area of square=\(8^2=64\) sq unit

Ans. (E)
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Re: The area of the circumscribed circle in the figure above is 32π. What [#permalink]
23 Aug 2018, 04:27
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