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 It is currently 22 Feb 2019, 19:06

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### Show Tags

28 Jan 2019, 22:40
3
00:00

Difficulty:

55% (hard)

Question Stats:

33% (02:34) correct 67% (02:04) wrong based on 10 sessions

### HideShow timer Statistics

The area of the region bounded by the curves $$y = \left | x-1 \right |$$ and $$y = \left | 3\right | - \left | x \right |$$ is _______ sq. units

A) 2
B) 3
C) 4
D) 5
E) 6

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Re: The area of the region bounded by the curves $y = \left | x-1 \right | [#permalink] ### Show Tags 29 Jan 2019, 06:15 4d wrote: The area of the region bounded by the curves $$y = \left | x-1 \right |$$ and $$y = \left | 3\right | - \left | x \right |$$ is _______ sq. units A) 2 B) 3 C) 4 D) 5 E) 6 IMO C y=|x−1| and y=|3|−|x| Hear me out on this, Just get the boundary values for the two modulus y=|x−1| => y = x-1 or y = -x+1 and plot on the graph by finding boundary values at (0,-1), (0,1) and (1,0) y=|3|−|x| => y = 3-x or y =-3+x by finding boundary values at (0,-3), (0,3) and (3,0) When plotted the points it should look like this > > We will get two triangles, bounded by 1,0 & 0,1 || 3,0 & 0,3 Area of a triangle 1/2 * 3* 3 - 1/2 * 1* 1 9/2 - 1/2 4 _________________ If you notice any discrepancy in my reasoning, please let me know. Lets improve together. Quote which i can relate to. Many of life's failures happen with people who do not realize how close they were to success when they gave up. Re: The area of the region bounded by the curves$y = \left | x-1 \right |   [#permalink] 29 Jan 2019, 06:15
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