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The average American spends y dollars on food per month, except during

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Joined: 27 Jan 2016
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The average American spends y dollars on food per month, except during [#permalink]

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New post 29 Jul 2017, 01:19
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Difficulty:

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Question Stats:

68% (01:23) correct 32% (01:10) wrong based on 73 sessions

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The average American spends y dollars on food per month, except during January, when food purchases are x percent lower than they are in other months. Which of the following represents food purchases, in dollars, for the first 9 months of a year?


A)9y – xy/100

B)9y + xy

C)9y – xy

D)(9y-xy)/9

E)y-xy/6
[Reveal] Spoiler: OA

Kudos [?]: 61 [0], given: 94

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Re: The average American spends y dollars on food per month, except during [#permalink]

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New post 29 Jul 2017, 01:48
Spends in Jan = (y - xy/100)
In other 8 months 8y

Total 8y + (y - xy/100)
=9y - xy/100 --A

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The average American spends y dollars on food per month, except during [#permalink]

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New post 29 Jul 2017, 11:06
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srikanth9502 wrote:
The average American spends y dollars on food per month, except during January, when food purchases are x percent lower than they are in other months. Which of the following reepresents food purchases, in dollars, for the first 9 months of a year?

A)9y – xy/100

B)9y + xy

C)9y – xy

D)(9y-xy)/9

E)y-xy/6

Assign values.

Let y dollars per month be 10
Let x percent less for January be 10

Eight month total is (8 * 10) = $80
January total is (.90)(10) = $9
Total for nine months = $89

With y = 10 and x = 10, find the answer choice that yields $89.

Answers B, C, D, and E can be eliminated quickly.

Answer B is 9y + xy. 9y = (9*10) = 90 is too high already. Adding anything will make it higher.

Answer C, 9y – xy. Easy and quick calculation shows result is negative.
(9*10) + (10*10) =
(90) - (100) = -10

If C is negative, then Answer D, (9y-xy)/9, is too. Its numerator is identical to answer C.

If C is negative with (9y - xy), then Answer E's numerator, 1y - xy, will be more negative.

Answer A, which initially looked strange because I read the denominator incorrectly, remains: 9y – xy/100

(9 * 10) - \(\frac{(10*10)}{100}\) =

90 - 1 = 89
Answer A

Kudos [?]: 265 [1], given: 552

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Re: The average American spends y dollars on food per month, except during [#permalink]

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New post 12 Aug 2017, 12:48
The amount for nine months: 9y

The amount for the January: y(x/100) = xy/100

What we're looking for is the amount spent for the first eight months of the year which would be the difference between nine months and the amount spent in January. This can be written algebraically as: 9y - xy/100

Which is answer choice A.

Kudos [?]: 0 [0], given: 524

Re: The average American spends y dollars on food per month, except during   [#permalink] 12 Aug 2017, 12:48
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