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# The average( arithmetic mean) of daily maximum temperature

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The average( arithmetic mean) of daily maximum temperature [#permalink]

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29 Jul 2003, 17:26
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The average( arithmetic mean) of daily maximum temperature at a certain water station from July 1 to July 19 was 5 degrees higher than the average daily maximum temperature from July 13th to July18th.
What is the maximum temperature on July 12th?

1) Average daily maximum temperature from July 13th to July 18th was 4 degrees less than the maximum temp on July 19th.

2) The average daily maximum temperature from July 12th to July 10th was 84 degrees.

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Last edited by Curly05 on 29 Jul 2003, 18:06, edited 1 time in total.
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29 Jul 2003, 17:35
Curly05 wrote:
The average( arithmetic mean) of daily maximum temperature at a certain water station from July 1 to July 19 was 5 degrees higher than the average daily maximum temperature from July 13th to July18th.

1) Average daily maximum temperature from July 13th to July 18th was 4 degrees less than the maximum temp on July 19th.

2) The average daily maximum temperature from July 12th to July 10th was 84 degrees.

You have once again forgotten to include the question so explaining the answer "with" clarity (know your idioms) will be problematic at best....
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

Eternal Intern
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30 Jul 2003, 06:48
Akami, feel free to take alook at it again.

vT
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Eternal Intern
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30 Jul 2003, 18:47
Feel free to take alook at chief or Stolyar
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31 Jul 2003, 10:09
Anyone solved this problem? I could not do it and will mark (e).
Thanks
Eternal Intern
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31 Jul 2003, 10:11
It can be solved, it is C, it is the hardest one on the CD-ROm.

VT
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31 Jul 2003, 11:34
Are you sure you typed this question in 100% accurately? I'm struggling to see how this question, as it is written, is not E. My logic is that I don't see anything that distinguishes the 10th-12th in any way. All we have is an average for those 3 days, and we know that those 3 days are included in the 19 days. Hence, even if we could solve down to get the average of the 10th-12th, we could make 10,11, and 12 any values we wanted to work to that average.
Eternal Intern
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31 Jul 2003, 13:41
I will ask Kaplan people to see if It can be solved.
VT
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Hi   [#permalink] 31 Jul 2003, 13:41
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