It is currently 28 Jun 2017, 07:14

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# The average (arithmetic mean) of the 5 positive integers k,

Author Message
SVP
Joined: 14 Dec 2004
Posts: 1689
The average (arithmetic mean) of the 5 positive integers k, [#permalink]

### Show Tags

04 Mar 2006, 12:34
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

A. 16
B. 18
C. 19
D. 20
E. 22
VP
Joined: 29 Dec 2005
Posts: 1341
Re: PS: Greatest possible median [#permalink]

### Show Tags

04 Mar 2006, 13:25
vivek123 wrote:
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22

total sum = 80
t = 40
rest (k+m+r+s) = 40

given that, median = r.
r is gretest when (k+m) is least and r = s but r cannot be equal to s because s>r.

so lets suppose k+m = 1+2 = 3, then r+s = 37.

the gretest r = 18
Intern
Joined: 08 Jan 2006
Posts: 27
Re: PS: Greatest possible median [#permalink]

### Show Tags

04 Mar 2006, 13:32
vivek123 wrote:
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

A. 16
B. 18
C. 19
D. 20
E. 22

B.

k+m+r+s+t/5 = 16
since t=40 then k+m+r+s = 40

Median of k,m,r,s, and t is r since they are increasing order.

so r+s<40
R cannot be >20 because s which is > r has to be > 20.
If r = 19, s will be 20 and then m can be 1 and k will be 0. But 0 is not a positive integer.
So r = 18, which makes s=19 and m=2 and k = 1.
SVP
Joined: 14 Dec 2004
Posts: 1689

### Show Tags

04 Mar 2006, 20:07

t = 40.

k < m < r < s < t

For 'r' to be greatest possible, s-r = 1
if r = 16 then s = 17 => r+s = 33 (still there is room for k & m)
if r = 18 then s = 19 => r+s = 37 (still there is room for k & m, boundary case & hence the answer)
if r = 19 then s = 20 => r+s = 40 (no room for k & m)

04 Mar 2006, 20:07
Display posts from previous: Sort by