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# The average (arithmetic mean) weight of two men is x, which

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Current Student
Joined: 29 Jan 2005
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The average (arithmetic mean) weight of two men is x, which [#permalink]

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14 Oct 2005, 08:06
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The average (arithmetic mean) weight of two men is x, which is twice the average weight of three different men. What is the average weight of all five men in terms of x?

Kudos [?]: 440 [0], given: 0

Senior Manager
Joined: 02 Oct 2005
Posts: 297

Kudos [?]: 24 [0], given: 0

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14 Oct 2005, 08:27
I think the answer is 7x/10.

(2*x + 3 * x/2) / 5
= ( (4x + 3x)/2)/5

= 7x/10

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Director
Joined: 21 Aug 2005
Posts: 785

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14 Oct 2005, 08:34
Total wt of 2 -> 2x
Total wt of other 3 -> (x/2)*3

Total Avg -> (4x+3x/2)/5 = 7x/10

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VP
Joined: 22 Aug 2005
Posts: 1111

Kudos [?]: 128 [0], given: 0

Location: CA

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14 Oct 2005, 08:34
sudhagar wrote:
I think the answer is 7x/10.

(2*x + 3 * x/2) / 5
= ( (4x + 3x)/2)/5

= 7x/10

You right. Missed the obvious, as usual

Kudos [?]: 128 [0], given: 0

Current Student
Joined: 29 Jan 2005
Posts: 5201

Kudos [?]: 440 [0], given: 0

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14 Oct 2005, 09:08
OA is 7X/10. Sud caught it.

Kudos [?]: 440 [0], given: 0

14 Oct 2005, 09:08
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# The average (arithmetic mean) weight of two men is x, which

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