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Re: The average (arithmetic mean) weight of two men is x, which is twice [#permalink]
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Bunuel wrote:
The average (arithmetic mean) weight of two men is x, which is twice the average weight of three different men. Which of the following expresses the average weight of all five men in terms of x?

A. x/2
B. 3x/5
C. 7x/2
D. 7x/10
E. 8x/5


Let the weights of men be a, b, c, d and e respectively

Average weight of 2 men = x
--> (a + b)/2 = x
--> a + b = 2x ....... (1)

Given x is twice the average weight of three different men
--> x = 2(c + d + e)/3
--> c + d + e = 3x/2 ....... (2)

Average weight of 5 men = (a + b + c + d + e)/5 = (2x + 1.5x)/5 = 3.5x/5 = 7x/10

IMO Option D
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Re: The average (arithmetic mean) weight of two men is x, which is twice [#permalink]
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