Abhi077 wrote:
The average of 63, 37 and x is greater than the average of the multiples of 3 between 1 and 111, inclusive. Which of the following is a possible value of x?
I. 64 II. 71 III. 75 IV. 85
A) I, II, Ill, and IV
B) IV only
C) II, Ill and IV
D) III and IV
E). None of these
rule: avg=sum•n
rule: multiple(x) between range: greatestm(x)-leastm(x)/x+1
rule: average of an arithmetic progression: greatestm(x)+leastm(x)/2
rule: any number is divisible by 3 if the sum of its digits is divisibly by 3
avg m(3) from 1 to 111 inclusive: greatestm(3)=111, leastm(3)=3, avg=111+3/2=57
given:
[63+37+x]/3>57
100+x>171
x>71
Answer (D).