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Re: The average of temperatures at noontime from Monday to Friday is 50; [#permalink]

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09 Jul 2011, 20:19

1

This post was BOOKMARKED

Alchemist1320 wrote:

The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?

20 25 40 45 75

there are 5 days so the sum of temperature can be 50*5=250 lowest is 45. to find the maximum range we can say the temperature was the lowest for 4 of the 5 days so 4*45=180. on the fifth day it is 250-180=70 range is therefore 70-45=25 answer B If 70 was one of the answer choices I am afraid I would have overlooked the range and chosen it

Re: The average of temperatures at noontime from Monday to Friday is 50; [#permalink]

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18 Dec 2016, 10:34

Nice Question. Here is what i did in this one =>

Let the values in increasing order be --> w1 w2 w3 w4 w5

Using -->

\(Mean =\frac{Sum}{#}\)

Sum(5)=50*5=250 Now w1=45

To maximise the range we must maximise w5. To maximize w5,we must minimise all others. Since no median constraint is provided ->Set will look like -> w1,w1,w1,w1,w5 => 4w1+w5=250 w5=70 Hence Range = 70-45=25

Re: The average of temperatures at noontime from Monday to Friday is 50; [#permalink]

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14 Jun 2017, 21:04

stonecold wrote:

Nice Question. Here is what i did in this one =>

Let the values in increasing order be --> w1 w2 w3 w4 w5

Using -->

\(Mean =\frac{Sum}{#}\)

Sum(5)=50*5=250 Now w1=45

To maximise the range we must maximise w5. To maximize w5,we must minimise all others. Since no median constraint is provided ->Set will look like -> w1,w1,w1,w1,w5 => 4w1+w5=250 w5=70 Hence Range = 70-45=25

Hence B

Hi, Nic explanation, i have just one question though, w5 can be maximised by assuming any hypothertical value...say 1000000 deg....other variables shall get automatically adjusted

Is this question complete? Thanx Anxiously awaiting reply

Re: The average of temperatures at noontime from Monday to Friday is 50; [#permalink]

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15 Jun 2017, 00:31

saurabhsavant wrote:

stonecold wrote:

Nice Question. Here is what i did in this one =>

Let the values in increasing order be --> w1 w2 w3 w4 w5

Using -->

\(Mean =\frac{Sum}{#}\)

Sum(5)=50*5=250 Now w1=45

To maximise the range we must maximise w5. To maximize w5,we must minimise all others. Since no median constraint is provided ->Set will look like -> w1,w1,w1,w1,w5 => 4w1+w5=250 w5=70 Hence Range = 70-45=25

Hence B

Hi, Nic explanation, i have just one question though, w5 can be maximised by assuming any hypothertical value...say 1000000 deg....other variables shall get automatically adjusted

Is this question complete? Thanx Anxiously awaiting reply

Absolutely not. You cannot assume W5 to be 1000000000

Look at the minimum value => 45 The other values must be greater than or equal to 45 since 45 is the minimum.

SO basically there are two constraints => One => Sum = 250 Two => Least temperature is 45.

The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?

20 25 40 45 75

Since the average of 5 daily temperatures is 50, the sum is 250. To maximize the range, we want one value to be as large as possible. This is done by minimizing the other 4 values. We can minimize the temperatures for 4 of the days, so the sum of the temperatures for those 4 days is 45 x 4 = 180. Thus, the final, maximum temperature, is 250 - 180 = 70 and the maximum range is 70 - 45 = 25.

Answer: B
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