We have two points A(p,q) and B(r,s) on the co-ordinate plane. Note that these points can be in any of the four quadrants and hence pay due attention to the signs of the co-ordinates as well.
In the question, we are trying to find if the absolute value of q is more than the absolute value of s.
Statement II alone does not give us any information about the question we are trying to answer, since it only talks about p and r. Therefore, let us eliminate options B and D since statement II alone is insufficient.
The possible answer options at this stage are A, C or E.
From statement I alone, we only know that the two points are equidistant from the origin.
If we take A(3,4) and B(4,3), both points are equidistant from the origin. In this case q = 4 and s = 3 and hence |q| > |s|.
If we take A(1,1) and B(-1,-1), both points are equidistant from the origin, but |q| = |s|.
Statement I alone is insufficient. Answer option A can be eliminated, possible answer options are C or E.
Combining statements I and II, we know that A and B are equidistant from the origin, and |p| > |r|.
Since A and B are equidistant from the origin, \(p^2 + q^2 = r^2 + s^2\). Also, distance of p from ZERO on x-axis is higher than the distance of r from ZERO on the x-axis (remember that p and r are the x co-ordinates).
If the equation above has to be satisfied, then distance of q from ZERO on y-axis should be lower than the distance of s from ZERO on y-axis. This is to balance out the equation. Otherwise, the LHS would become greater than the RHS.
Another easy way of understanding this concept is by looking at co-ordinates like (4,3) and (3,4). Here since |p|>|r|, you can observe that |q|<|s|. If you take the case of (1,1) and (-1,-1), you see that |p| = |r| and hence it turns out that |q| = |s| so that the equation holds.
The combination of statements is sufficient to say |q| < |s| and answer the question with a definite NO. Answer option E can be eliminated.
The correct answer option is C.
Hope that helps!
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