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Updated on: 25 Nov 2019, 04:43
00:00

Difficulty:

35% (medium)

Question Stats:

69% (01:16) correct 31% (02:39) wrong based on 16 sessions

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The cost (in $) of a watermelon is proportional to the square root of its weight (in pounds). If a watermelon weighing 16 pounds costs$50, how much will a watermelon costing $37.5 weigh, in pounds? (A) 4 (B) 8 (C) 9 (D) 12 (E) 15 Originally posted by CaptainLevi on 25 Nov 2019, 04:29. Last edited by CaptainLevi on 25 Nov 2019, 04:43, edited 1 time in total. Manager Joined: 16 Feb 2015 Posts: 176 Location: United States Concentration: Finance, Operations Schools: INSEAD, ISB Re: The cost (in$) of a watermelon is proportional to the square root  [#permalink]

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25 Nov 2019, 04:41
CaptainLevi wrote:
The cost (in Rs.) of a watermelon is proportional to the square root of its weight (in pounds). If a watermelon weighing 16 pounds costs $50, how much will a watermelon costing$37.5 weigh, in pounds?

(A) 4
(B) 8
(C) 9
(D) 12
(E) 15

I think answer should be D.
As 50 $( Which is 12.5$ X 4)= 16 (4x4) pounds
12.5$* 3 = 37.5$
Similarly, 4 * 3 =12

So answer is D
Intern
Joined: 28 Nov 2017
Posts: 12

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11 Dec 2019, 16:58
Let C = cost and P = pounds.

The question gives us the formula $$C = x \sqrt{P}$$.

Plugging in the initial values, we have:

$$50 = x \sqrt{16}$$
$$50 = x (4)$$
$$x = 12.5$$

Now with the new info:

$$37.5 = 12.5\sqrt{P}$$
$$3 = \sqrt{P}$$
$$9 = P$$

The Answer is C.
Re: The cost (in $) of a watermelon is proportional to the square root [#permalink] 11 Dec 2019, 16:58 Display posts from previous: Sort by # The cost (in$) of a watermelon is proportional to the square root

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