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The cost of a certain phone call was $0.75 for the first 3 minutes and

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The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  17 Dec 2013, 17:06
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The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes?

(1) The cost of the phone call was less than $4.16.

(2) The cost of the phone call was greater than $3.35.


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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  18 Dec 2013, 01:39
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Bunuel wrote:
megafan wrote:
The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

(1) The cost of the phone call was less than $4.16
(2) The cost of the phone call was greater than $3.35



While this is a seemingly simple min/max problem, I was wondering if there is a faster way to deal with decimals—as it took me ~4mins to arrive at the solution.


The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

According to the above the cost for n minutes, where n>3, is \(75 + (n-3)*20=20n+15\) cents. W need to find whether n>15. The cost for 15 minutes is \(20n+15=20*15+15=315\) cents, so we need to find whether the cost is greater than 315 cents.

(1) The cost of the phone call was less than $4.16. Not sufficient.

(2) The cost of the phone call was greater than $3.35. Sufficient.

Answer: B.


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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  18 Dec 2013, 01:34
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megafan wrote:
The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

(1) The cost of the phone call was less than $4.16
(2) The cost of the phone call was greater than $3.35



While this is a seemingly simple min/max problem, I was wondering if there is a faster way to deal with decimals—as it took me ~4mins to arrive at the solution.


The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

According to the above the cost for n minutes, where n>3, is \(75 + (n-3)*20=20n+15\) cents. W need to find whether n>15. The cost for 15 minutes is \(20n+15=20*15+15=315\) cents, so we need to find whether the cost is greater than 315 cents.

(1) The cost of the phone call was less than $4.16. Not sufficient.

(2) The cost of the phone call was greater than $3.35. Sufficient.

Answer: B.
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  02 Jul 2014, 08:05
Hi Bunuel,
I tried solving this question by following method and i feel both the statements are not sufficient to get an answer.

given: The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

let's assume phone call lasted for x mins
1) The cost of the phone call was less than $4.16
75+x*20< 416
x<17.04.. Not sufficient as x can be > , < or = 15

2) The cost of the phone call was greater than $3.35
75+x*20>335
x>13 again not sufficient

combining both 13<x<17..not sufficient..
Please let me know where i am going wrong.
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  02 Jul 2014, 21:26
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varikaur wrote:
Hi Bunuel,
I tried solving this question by following method and i feel both the statements are not sufficient to get an answer.

given: The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

let's assume phone call lasted for x mins
1) The cost of the phone call was less than $4.16
75+x*20< 416
x<17.04.. Not sufficient as x can be > , < or = 15

2) The cost of the phone call was greater than $3.35
75+x*20>335
x>13 again not sufficient

combining both 13<x<17..not sufficient..
Please let me know where i am going wrong.


I get the fallacy mate. The call of 0.20 is after three minutes. So once you as per you calculation get 13 , you have to add the first 3 minutes. Thus you get the total time as 13 + 3 = 16 minutes
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  02 Dec 2014, 21:00
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Lets t = 15 then C = .75 + 12*.20 = 3.15. basically is C > $3.15

1. C < 4.16 not sufficient
2. C > 3.35 so C is definitely greater then 3.15 Sufficient.

Answer: B

megafan wrote:
The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

(1) The cost of the phone call was less than $4.16
(2) The cost of the phone call was greater than $3.35



While this is a seemingly simple min/max problem, I was wondering if there is a faster way to deal with decimals—as it took me ~4mins to arrive at the solution.
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  09 Aug 2016, 18:39
Bunuel wrote:
megafan wrote:
The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

(1) The cost of the phone call was less than $4.16
(2) The cost of the phone call was greater than $3.35



While this is a seemingly simple min/max problem, I was wondering if there is a faster way to deal with decimals—as it took me ~4mins to arrive at the solution.


The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

According to the above the cost for n minutes, where n>3, is \(75 + (n-3)*20=20n+15\) cents. W need to find whether n>15. The cost for 15 minutes is \(20n+15=20*15+15=315\) cents, so we need to find whether the cost is greater than 315 cents.

(1) The cost of the phone call was less than $4.16. Not sufficient.

(2) The cost of the phone call was greater than $3.35. Sufficient.

Answer: B.


What is the flaw in my reasoning -

0.75X3 + A X 0.2 = Total Cost.

Where A is the # of Minutes after 3 Minutes.

Basically, now we boil down to if A>12

Statement 1 =
0.75X3 + A X 0.2 = 4.16
A = 9.55 Minutes - That means A is not greater than 12. Hence with the calculation we did above we can clearly say that this statement is sufficient to forecast that A is not greater than 12.
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  10 Aug 2016, 01:06
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RichaChampion wrote:
Bunuel wrote:
megafan wrote:
The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

(1) The cost of the phone call was less than $4.16
(2) The cost of the phone call was greater than $3.35



While this is a seemingly simple min/max problem, I was wondering if there is a faster way to deal with decimals—as it took me ~4mins to arrive at the solution.


The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

According to the above the cost for n minutes, where n>3, is \(75 + (n-3)*20=20n+15\) cents. W need to find whether n>15. The cost for 15 minutes is \(20n+15=20*15+15=315\) cents, so we need to find whether the cost is greater than 315 cents.

(1) The cost of the phone call was less than $4.16. Not sufficient.

(2) The cost of the phone call was greater than $3.35. Sufficient.

Answer: B.


What is the flaw in my reasoning -

0.75X3 + A X 0.2 = Total Cost.

Where A is the # of Minutes after 3 Minutes.

Basically, now we boil down to if A>12

Statement 1 =
0.75X3 + A X 0.2 = 4.16
A = 9.55 Minutes - That means A is not greater than 12. Hence with the calculation we did above we can clearly say that this statement is sufficient to forecast that A is not greater than 12.


You should read the stem and the solution more carefully.

1. The cost of a certain phone call was $0.75 for the first 3 minutes, not $0.75 for each of the first 3 minutes;
2. A in your solution must be more than 15, not more than 12;
3. (1) says that the cost of the phone call was less than $4.16, not equal to $4.16.

So, it should be 0.75+ A *0.2 < 4.16 --> A < 17.05.
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  05 Sep 2016, 12:03
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The trick here is understanding that the 0,75 was for all three minutes (not 0,75 per minute).
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  02 Dec 2017, 10:55
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megafan wrote:
The cost of a certain phone call was $0.75 for the first 3 minutes and $0.20 for each additional minute after the first 3 minutes. Did the phone call last longer than 15 minutes

(1) The cost of the phone call was less than $4.16
(2) The cost of the phone call was greater than $3.35


For First 3 mins, the cost = 0.75$
For each additional minute after the first 3 minutes, the cost = 0.20$

SO, calculate the cost for the 15 minutes -- cost for first 3 mins + cost for each additional minute after the first 3 minutes
= 0.75$ + 12*0.20$ = 0.75$ + 2.40$ = 3.15$

Now, Question becomes whether the cost of phone call > 3.15$?

1. <4.16$
so the cost can OR cannot be > 3.15$ Insufficient

2. >3.35$
Sufficient. As cost > 3.35$ will always be > than 3.15$.

Answer : B
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Re: The cost of a certain phone call was $0.75 for the first 3 minutes and [#permalink] New post  23 Jan 2019, 23:44
For a 15 minute call, the call cost will be 3.15 dollars.
A call greater than 15 minutes will have to cost more than 3.15 dollars.

Statement 1 - Not sufficient.
Statement 2 - Sufficient.

Hence B.
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