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The equation of line a is x = (y - 6)/5. If line m has a negative

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The equation of line a is x = (y - 6)/5. If line m has a negative  [#permalink]

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New post 05 Sep 2018, 23:41
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Question Stats:

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The equation of line a is \(x = \frac{y - 6}{5}\). If line m has a negative reciprocal slope to line a and passes through point (2, –4) what is the y-intercept of line m?


A. –14
B. –4.4
C. –3.6
D. 4.4
E. 6

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Re: The equation of line a is x = (y - 6)/5. If line m has a negative  [#permalink]

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New post 06 Sep 2018, 02:22
Bunuel wrote:
The equation of line a is \(x = \frac{y - 6}{5}\). If line m has a negative reciprocal slope to line a and passes through point (2, –4) what is the y-intercept of line m?


A. –14
B. –4.4
C. –3.6
D. 4.4
E. 6


Equation of line a, \(x = \frac{y - 6}{5}\)

i.e. Equation of line a,\(y = 5x + 6\)

i.e. Slope of line a = 5 (after comparing this equation with general equation of line i.e. \(y = mx+c\))

i.e. Slope of line m \(= -(1/5)\)

Hence, equation of line m, \(y = -(1/5)x + C\) . where c is is Y-intercept of line m

But since this line passes through point (2, -4) hence this point must satisfy the equation of line m

i.e. \((-4) = -(1/5)(2) + C\)
i.e. C = (-18/5) = -3.6

Answer: option C
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Re: The equation of line a is x = (y - 6)/5. If line m has a negative &nbs [#permalink] 06 Sep 2018, 02:22
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