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# The equation of line a is x = (y - 6)/5. If line m has a negative

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Math Expert
Joined: 02 Sep 2009
Posts: 49231
The equation of line a is x = (y - 6)/5. If line m has a negative  [#permalink]

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06 Sep 2018, 00:41
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Difficulty:

35% (medium)

Question Stats:

70% (01:38) correct 30% (01:41) wrong based on 23 sessions

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The equation of line a is $$x = \frac{y - 6}{5}$$. If line m has a negative reciprocal slope to line a and passes through point (2, –4) what is the y-intercept of line m?

A. –14
B. –4.4
C. –3.6
D. 4.4
E. 6

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Re: The equation of line a is x = (y - 6)/5. If line m has a negative  [#permalink]

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06 Sep 2018, 03:22
Bunuel wrote:
The equation of line a is $$x = \frac{y - 6}{5}$$. If line m has a negative reciprocal slope to line a and passes through point (2, –4) what is the y-intercept of line m?

A. –14
B. –4.4
C. –3.6
D. 4.4
E. 6

Equation of line a, $$x = \frac{y - 6}{5}$$

i.e. Equation of line a,$$y = 5x + 6$$

i.e. Slope of line a = 5 (after comparing this equation with general equation of line i.e. $$y = mx+c$$)

i.e. Slope of line m $$= -(1/5)$$

Hence, equation of line m, $$y = -(1/5)x + C$$ . where c is is Y-intercept of line m

But since this line passes through point (2, -4) hence this point must satisfy the equation of line m

i.e. $$(-4) = -(1/5)(2) + C$$
i.e. C = (-18/5) = -3.6

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Re: The equation of line a is x = (y - 6)/5. If line m has a negative &nbs [#permalink] 06 Sep 2018, 03:22
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