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The equation of line m is y=x/2+1. What is the distance from the x-int

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The equation of line m is y=x/2+1. What is the distance from the x-int [#permalink]

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New post 08 Sep 2016, 04:20
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The equation of line m is y=x/2+1. What is the distance from the x-intercept of m to the intersection of x=4 and m?

A. √(13)
B. 5
C. 6
D. 3√5
E. 7

[Reveal] Spoiler:
Attachment:
T6207.png
T6207.png [ 4.43 KiB | Viewed 1761 times ]
[Reveal] Spoiler: OA

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Re: The equation of line m is y=x/2+1. What is the distance from the x-int [#permalink]

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New post 08 Sep 2016, 06:15
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firstly, x intercept of Line m:
sub y=0 in y=x/2 + 1
x=-2 (the x intercept of line m)

Second step:

Intersection of line x=4 & line m

Solving the equations y=x/2 + 1 & x=4,
the x, y points of intersection are (4, 3)

Hence Line m, Line x=4 & x intercept of Line m form a Right angle triangle with points (4,3) (4,0) and (-2,0)

Further applying Hyp. thoerem: the distance from the x-intercept of m to the intersection of x=4 and m
=√(6^2+3^2)
=√(35)
=3√5

Option D
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Re: The equation of line m is y=x/2+1. What is the distance from the x-int [#permalink]

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New post 02 Apr 2017, 23:58
Intersection point for this line with x = 4 is (4,3)

X intersection point for the line is = (-2, 0)

Distance between two points is - \(\sqrt{(y1 - y2)^2 + (x1-x2)^2}\)

\(\sqrt{(3-0)^2 + (4- (-2))^2}\)

\(\sqrt{9+ 36}\)

\(\sqrt{45}\)

\(3\sqrt{5}\)
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Re: The equation of line m is y=x/2+1. What is the distance from the x-int [#permalink]

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New post 17 Apr 2017, 15:55
i failed this question miserably...
idk I thought I'm asked for the area of the "triangle"...so i multiplied 6 with 2 (IDK why I got 2 when clearly it's y=3 when x=4) and divided by 2...
it's clearly C....
we get a right angle triangle, with legs equal to 6 and 3.
6^2 + 3^2 = what we need^2
36+9=45
sqrt(45) = 3*sqrt(5)
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Re: The equation of line m is y=x/2+1. What is the distance from the x-int [#permalink]

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New post 28 Nov 2017, 06:56
Bunuel wrote:
Image
The equation of line m is y=x/2+1. What is the distance from the x-intercept of m to the intersection of x=4 and m?

A. √(13)
B. 5
C. 6
D. 3√5
E. 7

[Reveal] Spoiler:
Attachment:
T6207.png



But x= 4 and m will never intersect .. Isn't it? m will just pass above from x = 4 but not intersect ...please explain someone
Re: The equation of line m is y=x/2+1. What is the distance from the x-int   [#permalink] 28 Nov 2017, 06:56
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