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The factorial expression 13!/7! is not divisible by which of the follo

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Bunuel
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The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   02 Jun 2016, 04:46
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The factorial expression 13!/7! is not divisible by which of the following integers?

(A) 3
(B) 5
(C) 6
(D) 7
(E) 9
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D
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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   02 Jun 2016, 11:33
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Bunuel wrote:
The factorial expression 13!/7! is not divisible by which of the following integers?

(A) 3
(B) 5
(C) 6
(D) 7
(E) 9


13!/7! => 13 x 12 x 11 x 10 x 9 x 8

(A) 3 Can divide 12 or 9
(B) 5 Can divide 10
(C) 6 Can divide 12
(D) 7 None of the Multiplicands present
(E) 9 Can divide 9

Hence answer will be (D)
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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   02 Jun 2016, 06:13
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Bunuel wrote:
The factorial expression 13!/7! is not divisible by which of the following integers?

(A) 3
(B) 5
(C) 6
(D) 7
(E) 9


13!/7! can be written as 13*12*11*10*9*8

There is no factor of 7 in this expression. Hence D is the answer
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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   02 Jun 2016, 11:26
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13!/7!
= (13*12 * 11 *10 * 9 * 8 * 7!)/7!
= 13*12 * 11 * 10 * 9*8
The given factorial expression is not divisible by 7
Answer D
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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   02 Jun 2016, 05:51
13!/7! can be reduced to 13*12*11*.... 8.

We can see that out of the options provided to us, 7 is not a part of this number. Hence D.
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The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   04 Jun 2016, 13:32
Bunuel wrote:
The factorial expression 13!/7! is not divisible by which of the following integers?

(A) 3
(B) 5
(C) 6
(D) 7
(E) 9



Factorial expression \(\frac{13!}{7!}\)=13*12*11*10*9*8 ,which is divisible by each answer choice except D.

So the Correct Answer is D
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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   17 Jul 2017, 15:13
= 13*12*11*10*9*8

As we check the answer choices we see we are not having any integer that number 7 can divide.

Hence, Answer is D

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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   05 Aug 2020, 13:48
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Bunuel wrote:
The factorial expression 13!/7! is not divisible by which of the following integers?

(A) 3
(B) 5
(C) 6
(D) 7
(E) 9


\(\frac{13!}{7!} = \frac{(13)(12)(11)(10)(9)(8)(7)(6)(5)(4)(3)(2)(1)}{(7)(6)(5)(4)(3)(2)(1)}=(13)(12)(11)(10)(9)(8)\)

(13)(12)(11)(10)(9)(8) is divisible by 3, because (13)(12)(11)(10)(9)(8) = (13)(12)(11)(10)(3)(3)(8). Eliminate A
(13)(12)(11)(10)(9)(8) is divisible by 5, because (13)(12)(11)(10)(9)(8) = (13)(12)(11)(5)(2)(9)(8). Eliminate B
(13)(12)(11)(10)(9)(8) is divisible by 6, because (13)(12)(11)(10)(9)(8) = (13)(7)(2)(11)(10)(9)(8). Eliminate C
(13)(12)(11)(10)(9)(8) is divisible by 6, because (13)(12)(11)(10)(9)(8) = (13)(12)(11)(10)(9)(8). Eliminate E

Answer: D

Cheers,
Brent
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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink] New post   14 Mar 2024, 03:02
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Re: The factorial expression 13!/7! is not divisible by which of the follo [#permalink]
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