htbreme wrote:
Hi everyone,
I wanted to make you a quick and apparently easy question that it's giving me a hard time:
What is the angle formed by the diagonals of to perpendicular faces of a cube?
I know the answer but I can't visualize why that's the answer
Source: local GMAT course
Thanks in advance
Added a question about this issue for a better understating.
Attachment:
The attachment Cube.jpg is no longer available
The figure above is a cube. What is the measure of angle BEG (not shown)?A. 30°
B. 45°
C. 60°
D. 75°
E. 90°
Note that triangle BEG is equilateral: it's made by the diagonals of the adjacent faces of the given cube (and as faces of a cube are squares its diagonals are equal). Thus angle BEG=60 degrees.
Answer: C.
Hope it helps.
Why isn't it 90? Since two diagonals bisect two 90 degree angles would the x angle equal to 90? I understand your explanation, but would like to understand why my thinking is wrong? Thank you.