Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 07:48

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# The figure above represents a square garden that is divided

Author Message
Senior Manager
Joined: 28 Jun 2007
Posts: 317
Followers: 1

Kudos [?]: 40 [0], given: 0

The figure above represents a square garden that is divided [#permalink]

### Show Tags

15 Sep 2007, 16:20
00:00

Difficulty:

(N/A)

Question Stats:

63% (01:31) correct 38% (01:45) wrong based on 37 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The figure above represents a square garden that is divided into 9 rectangular regions with indicated dimensions in meters. The shaded regions are planted with peas, and the unshaded regions are planted with tomatoes. If the sum of the areas of the regions planted with peas is equal to the sum of the areas of the regions planted with tomatoes, what is the value of x?

A. 0.5
B. 1
C. 1.5
D. 2
E. 2.5
Attachments

Q8.jpg [ 6.48 KiB | Viewed 9161 times ]

VP
Joined: 09 Jul 2007
Posts: 1102
Location: London
Followers: 6

Kudos [?]: 110 [0], given: 0

### Show Tags

15 Sep 2007, 16:51
3*3+3*3+(6-x)3+3*x+3*x=36+3x

3*3+(6-x)3+(6-x)3+3*x=45-3x

now S1=S2

36+3x=45-3x
6x=9
x=1.5

C

Last edited by Ravshonbek on 15 Sep 2007, 16:52, edited 1 time in total.
VP
Joined: 08 Jun 2005
Posts: 1145
Followers: 7

Kudos [?]: 213 [0], given: 0

### Show Tags

15 Sep 2007, 16:51
shaded regions = (9-3-x)*3+3*3+3*3+3x+3x = 18-3x+18+6x

unshaded regions = (9-3-x)*3+(9-3-x)*3+3*3+3x = 18-3x+18-3x+9+3x

since:

18-3x+18+6x = 18-3x+18-3x+9+3x

36+3x = 36-6x+9+3x

9 = 6x

x = 1.5

Current Student
Joined: 28 Dec 2004
Posts: 3363
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 15

Kudos [?]: 297 [0], given: 2

### Show Tags

16 Sep 2007, 08:55
nice works..now why didnt i think of solving it this way??
Senior Manager
Joined: 28 Jun 2007
Posts: 317
Followers: 1

Kudos [?]: 40 [0], given: 0

### Show Tags

16 Sep 2007, 11:46
OA is indeed C.
Director
Joined: 17 Sep 2005
Posts: 910
Followers: 4

Kudos [?]: 78 [0], given: 0

### Show Tags

16 Sep 2007, 18:30
Key is "square garden".

- Brajesh
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5045
Location: Singapore
Followers: 31

Kudos [?]: 376 [0], given: 0

### Show Tags

16 Sep 2007, 23:08
Ans :C.

Attachment is my working.
Attachments

plot.doc [37.5 KiB]

VP
Joined: 08 Jun 2005
Posts: 1145
Followers: 7

Kudos [?]: 213 [0], given: 0

### Show Tags

16 Sep 2007, 23:23
ywilfred wrote:
Ans :C.

Attachment is my working.

Nice work !

16 Sep 2007, 23:23
Display posts from previous: Sort by

# The figure above represents a square garden that is divided

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.