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The figure above shows a path around a triangular piece of land. Mary
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14 Oct 2015, 21:26
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The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked? (A) 30% (B) 40% (C) 50% (D) 60% (E) 80% Kudos for a correct solution.Attachment:
20151015_0825.png [ 4.43 KiB  Viewed 19186 times ]
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Re: The figure above shows a path around a triangular piece of land. Mary
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14 Oct 2015, 22:14
Bunuel wrote: The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked? (A) 30% (B) 40% (C) 50% (D) 60% (E) 80% Kudos for a correct solution.Attachment: 20151015_0825.png PR = \(\sqrt{8^2+6^2} = 10\) DIstance walked by Mary = 8+6 = 14 % Exceeded distance of Mary = (1410)*100/10 = 40% Answer: Option B
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Re: The figure above shows a path around a triangular piece of land. Mary
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15 Oct 2015, 01:52
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer. The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked? (A) 30% (B) 40% (C) 50% (D) 60% (E) 80% The total distance Mary walked is 8+6=14 miles, while the distance Ted walked is 10 miles( by the Pythagorean theorem √(8^2 +6^2)=√(100)=10). So Mary walked 4 miles more than Ted. That means Mary walked 40%((4/10)*100) more walked than Ted. So the answer is (B).
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Re: The figure above shows a path around a triangular piece of land. Mary
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17 Nov 2016, 09:36
Bunuel wrote: The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked? (A) 30% (B) 40% (C) 50% (D) 60% (E) 80% Kudos for a correct solution.Attachment: 20151015_0825.png The standard measurement of 90 degree scale is 345 So, if we multiply the measurement by 2 then I’ll get it as 6810. That means, PQ=10, So, Ted’s walk distance is 10. Distance walked by Mary = 8+6 = 14. So Mary walked 4 miles more than Ted. If I want to make 100% of Mary’s walk, I have to multiply it by 10. Simultaneously, Ted’s walk will be 4*10=40%. So the answer is (B)
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Re: The figure above shows a path around a triangular piece of land. Mary
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30 May 2017, 16:13
Attached is a visual that should help.
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Screen Shot 20170530 at 4.07.21 PM.png [ 133.22 KiB  Viewed 13110 times ]
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Re: The figure above shows a path around a triangular piece of land. Mary
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10 Dec 2017, 14:29
ANSWER SIMPLE: Area = 1/2 bh Area = 1/2 8*6 Area = 1/2 48 Area = 24
24  8  6 = distance Ted walked PR =10
Mary = 14 Ted = 10
Difference 4 Percentage difference 4/10 40%
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Re: The figure above shows a path around a triangular piece of land. Mary
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27 Jan 2018, 23:15
GMATinsight Bunuel niks18 chetan2u The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked? (A) 30% (B) 40% (C) 50% (D) 60% (E) 80% Quote: PR = \(\sqrt{8^2+6^2} = 10\)
DIstance walked by Mary = 8+6 = 14
% Exceeded distance of Mary = (1410)*100/10 = 40%
Answer: Option B Can experts suggest why we took 10 in denominator and not 14?
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Re: The figure above shows a path around a triangular piece of land. Mary
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27 Jan 2018, 23:27
adkikani wrote: GMATinsight Bunuel niks18 chetan2u The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked?(A) 30% (B) 40% (C) 50% (D) 60% (E) 80% Quote: PR = \(\sqrt{8^2+6^2} = 10\)
DIstance walked by Mary = 8+6 = 14
% Exceeded distance of Mary = (1410)*100/10 = 40%
Answer: Option B Can experts suggest why we took 10 in denominator and not 14? Hi adkikaniRead the highlighted part carefully. % will be (extra distance walked by Mary)/(Distance walked by Ted) We need a % over distance walked by Ted,



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Re: The figure above shows a path around a triangular piece of land. Mary
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04 Jun 2019, 08:46
We're told that the figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R and Ted walked directly from P to R. We're asked by what PERCENT the distance that Mary walked exceeded the distance that Ted walked. This question is based around Geometry patterns and the Percent Change Formula.



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Re: The figure above shows a path around a triangular piece of land. Mary
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05 Jun 2019, 00:01
Formula to be used: Pythagoras theorem: \(Hypotenuse^2\) = \(Base^2\) + \(Perpendicular^2\) Total distance walked by Mary = \(PQ + QR = 8 + 6 = 14 miles\) Total distance walked by Ted = PR Applying Pythagoras theorem in the Triangle PQR: \(PR^2\) = \(PQ^2\) + \(QR^2\) \(PR^2\) = \(8^2\) + \(6^2\) \(= 64 + 36 = 100\) PR = +10 OR 10 Since PR is a distance and cannot be negative, PR = 10 miles The difference in the distance walked by Mary and Ted = 14  10 = 4 miles Percent of the distance that Mary walked more than Ted walked = \(\frac{4}{10}\) * 100 = 40% The correct answer is B
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Re: The figure above shows a path around a triangular piece of land. Mary
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09 Jun 2019, 18:53
Bunuel wrote: The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked? (A) 30% (B) 40% (C) 50% (D) 60% (E) 80% Kudos for a correct solution.Attachment: 20151015_0825.png Since we have a right triangle, we see that we have a 6810 right triangle. Mary’s distance was 14, and Ted’s distance was 10, so Mary traveled 4 miles more than Ted. 4/10 = 40% Answer: B
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Re: The figure above shows a path around a triangular piece of land. Mary
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23 Jun 2019, 06:17
Bunuel wrote: The figure above shows a path around a triangular piece of land. Mary walked the distance of 8 miles from P to Q and then walked the distance of 6 miles from Q to R. If Ted walked directly from P to R, by what percent did the distance that Mary walked exceed the distance that Ted walked? (A) 30% (B) 40% (C) 50% (D) 60% (E) 80% Kudos for a correct solution.Attachment: 20151015_0825.png First, the real amount of time that this question should take us. 8 and 6, that means that this is a 10, and this is a 14. 14 exceeds 10 by 4, out of the original number which is a 10, that is 40%, that's it! The correct answer choice is B.
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Re: The figure above shows a path around a triangular piece of land. Mary
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