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# The figure above shows a rectangular garden that is

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SVP
Joined: 21 Jul 2006
Posts: 1513

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The figure above shows a rectangular garden that is [#permalink]

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28 Nov 2007, 09:34
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The figure above shows a rectangular garden that is comprised of a central plot and a border surrounding the central plot; the border and the central plot have the same area. The garden has length 25 feet and width 20 feet. If the length and width of the central plot have the same ratio as the length and width of the garden, what is the length of the central plot, in feet?

a) 25 sqrt(2)
b) 20 sqrt(2)
c) 20(1-sqrt(2))
d) ( 25 sqrt(2) ) / 2
e) (25/2) ( 25/2)

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VP
Joined: 22 Nov 2007
Posts: 1079

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28 Nov 2007, 10:29
tarek99 wrote:
The figure above shows a rectangular garden that is comprised of a central plot and a border surrounding the central plot; the border and the central plot have the same area. The garden has length 25 feet and width 20 feet. If the length and width of the central plot have the same ratio as the length and width of the garden, what is the length of the central plot, in feet?

a) 25 sqrt(2)
b) 20 sqrt(2)
c) 20(1-sqrt(2))
d) ( 25 sqrt(2) ) / 2
e) (25/2) ( 25/2)

The area of the global rectangle is 25*20, while the area of the central plot is l*w. Our aim is to calculate l. From the argument we know that the area of the border is equal to the area of the central plot, so 25*20 - lw=lw, thus lw=250. let's have a system with the other hipothesis l/w=25/20 and substitute w=20/25 l in the first equation. then we have l powered 2 =250*5/4 and it follows that the answer is d. doubts?

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Manager
Joined: 20 Jun 2007
Posts: 156

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28 Nov 2007, 10:34
I've been struggling with hard sums (quadratic equations and all that), but I think the answer might simply be process of elimination.

The answer has to be in the region of something less than 25, maybe 4 or 5 or 6, say 19 -21.

a) 25 sqrt(2)
Impossible = this comes to more than 25
b) 20 sqrt(2)
Impossible = this comes to more than 25
c) 20(1-sqrt(2))
Impossible - this is negative!
d) ( 25 sqrt(2) ) / 2
This is roughly 18
e) (25/2) ( 25/2)
This is more than 12^2, > 144

So there's only one possible answer - D

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SVP
Joined: 21 Jul 2006
Posts: 1513

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28 Nov 2007, 10:52
the OA is D. and I think marcodonzelli showed a very nice explanation to reach to an answer.

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CEO
Joined: 29 Mar 2007
Posts: 2554

Kudos [?]: 500 [0], given: 0

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28 Nov 2007, 11:22
tarek99 wrote:
The figure above shows a rectangular garden that is comprised of a central plot and a border surrounding the central plot; the border and the central plot have the same area. The garden has length 25 feet and width 20 feet. If the length and width of the central plot have the same ratio as the length and width of the garden, what is the length of the central plot, in feet?

a) 25 sqrt(2)
b) 20 sqrt(2)
c) 20(1-sqrt(2))
d) ( 25 sqrt(2) ) / 2
e) (25/2) ( 25/2)

z is the width of the frame. X is the length of the picture, Y is the width of the picture.

x+2z=25 y+2z=20 x/y=25/20 --> 5w/4w w is a multiplier.

25*20= total area so 500 -(x*y) = x*y so x*y=250.

x-y=5 y=x-5 --> x(x-5)=250 --> x^2-5x-250=0

From here I dont really know how to solve this quadratic.

I did what Raffie did. Only D works

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CEO
Joined: 17 Nov 2007
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Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

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28 Nov 2007, 13:12
shortcut:

S1/S0=1/2 ==> L1/L0=1/√2 ==> 25/√2

Kudos [?]: 4474 [0], given: 360

28 Nov 2007, 13:12
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