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The figure above shows squares PQRS and TUVW, each with side of length

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Math Expert
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The figure above shows squares PQRS and TUVW, each with side of length  [#permalink]

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New post 04 Oct 2017, 00:31
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A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

71% (02:09) correct 29% (02:06) wrong based on 48 sessions

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Re: The figure above shows squares PQRS and TUVW, each with side of length  [#permalink]

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New post 04 Oct 2017, 07:53
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1
Bunuel wrote:
Image
The figure above shows squares PQRS and TUVW, each with side of length 6, that lie on line n. If RM = MW, then RW =

(A) 2√3
(B) 6
(C) 4√3
(D) 6√2
(E) 10

Attachment:
2017-10-04_1121_001.png


Need to find \(RW=2RM\)

In triangle QRM & TMW, \(QR=TW\), \(RM=MW\) and angle \(QRM=TWM=90°\). Hence both the triangles are congruent

This implies angle \(QMR=TMW=60°\). Hence triangle QRM is a \(30°-60°-90°\) triangle so the ratio of sides will be \(1:\sqrt{3}:2\)

As \(QR=6\), so \(RM=\frac{6}{\sqrt{3}}\) \(=2\sqrt{3}\)

Hence \(RW=2*2\sqrt{3}=4\sqrt{3}\)

Option C
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Re: The figure above shows squares PQRS and TUVW, each with side of length  [#permalink]

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New post 06 Mar 2019, 10:10
Hello from the GMAT Club BumpBot!

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Re: The figure above shows squares PQRS and TUVW, each with side of length   [#permalink] 06 Mar 2019, 10:10
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The figure above shows squares PQRS and TUVW, each with side of length

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