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# The figure above shows the dimensions of a rectangular box

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Director
Joined: 09 Aug 2006
Posts: 521

Kudos [?]: 111 [0], given: 0

The figure above shows the dimensions of a rectangular box [#permalink]

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18 May 2007, 22:48
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

17. The figure above shows the dimensions of a rectangular box that is to be completely wrapped with paper. If a single sheet of paper is to be used without patching, then the dimensions of the paper could be
(A) 17 in by 25 in
(B) 21 in by 24 in
(C) 24 in by 12 in
(D) 24 in by 14 in
(E) 26 in by 14 in
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a.JPG [ 2.6 KiB | Viewed 844 times ]

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Current Student
Joined: 22 Apr 2007
Posts: 1097

Kudos [?]: 26 [0], given: 0

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18 May 2007, 22:54
B (My rough calculation says that we need 20 x 24 at least)

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Director
Joined: 09 Aug 2006
Posts: 521

Kudos [?]: 111 [0], given: 0

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18 May 2007, 23:08
This is how I solved it :

We would need to find the total surface area of the rectangle to know the dimension of the paper used to cover the Rectangle.

The Total surface would be :

2 x (8 x 2) + 2 x (20 x 2) + 2 x (20 x 8) = 32 + 80 + 320 = 432.

So we would need the paper whose area is 432 or the nearest but should be more. As per the OA, the answer is C which is 288 which is very less. Hence the confusion.

Kudos [?]: 111 [0], given: 0

Director
Joined: 09 Aug 2006
Posts: 521

Kudos [?]: 111 [0], given: 0

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18 May 2007, 23:11
Ohh goosshhh... I am sorry the OA is indeed B i.e 504.. I was looking at the wrong answer.. I am so stupid.. These kind of mistakes will drown me on the test... I deserve a kick on my @\$\$...

Thanks ..

Kudos [?]: 111 [0], given: 0

18 May 2007, 23:11
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# The figure above shows the dimensions of a rectangular box

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