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# The first three terms in an arithmetic sequence are 30, 33, and 36. Wh

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Math Expert
Joined: 02 Sep 2009
Posts: 58427
The first three terms in an arithmetic sequence are 30, 33, and 36. Wh  [#permalink]

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17 Dec 2018, 02:09
1
00:00

Difficulty:

15% (low)

Question Stats:

82% (00:55) correct 18% (00:48) wrong based on 45 sessions

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The first three terms in an arithmetic sequence are 30, 33, and 36. What is the 80th term?

A. 261
B. 264
C. 267
D. 270
E. 273

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Location: India
Concentration: Sustainability, Marketing
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The first three terms in an arithmetic sequence are 30, 33, and 36. Wh  [#permalink]

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17 Dec 2018, 03:49
Bunuel wrote:
The first three terms in an arithmetic sequence are 30, 33, and 36. What is the 80th term?

A. 261
B. 264
C. 267
D. 270
E. 273

an=a+(n-1)d

an=80 to be determined
n=80
a=30
d=3

so a80= 267 IMO C
The first three terms in an arithmetic sequence are 30, 33, and 36. Wh   [#permalink] 17 Dec 2018, 03:49
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