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# The graph shows the number of computers assembled during each of 6 con

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The graph shows the number of computers assembled during each of 6 con  [#permalink]

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Updated on: 16 Jun 2017, 09:48
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55% (hard)

Question Stats:

63% (01:43) correct 37% (01:39) wrong based on 1589 sessions

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The graph shows the number of computers assembled during each of 6 consecutive days.From what day to the next day was the percent change in the number of computers assembled the greatest in magnitude ?

A. From Day 1 to Day 2
B. From Day 2 to Day 3
C. From Day 3 to Day 4
D. From Day 4 to Day 5
E. From Day 5 to Day 6

Attachment:

zxwlzd.jpg [ 12 KiB | Viewed 18701 times ]

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Sentence Correction-Collection of Ron Purewal's "elliptical construction/analogies" for SC Challenges

Originally posted by AbdurRakib on 16 Jun 2017, 09:17.
Last edited by Bunuel on 16 Jun 2017, 09:48, edited 1 time in total.
Edited the question.
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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16 Jun 2017, 11:23
7
6
day 1 to day 2 = 20 to 12 = 8/20 * 100 = 40% change
day 2 to day 3 = 12 to 18 = 6/12 * 100 = 50% change
day 3 to day 4 = 18 to 10 = 8/18 * 100 = 44.44 % change
day 4 to day 5 = 10 to 16 = 6/10 * 100 = 60% change
day 5 to day 6 = 16 to 8 = 8/16 * 100 = 50% change

Clearly, day 4 to day 5 is MAX, hence D answer
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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16 Jun 2017, 09:29
2
AbdurRakib wrote:

The graph shows the number of computers assembled during each of 6 consecutive days.From what day to the next day was the percent change in the number of computers assembled the greatest in magnitude ?

A. From Day 1 to Day 2
B. From Day 2 to Day 3
C. From Day 3 to Day 4
D. From Day 4 to Day 5
E. From Day 5 to Day 6

Just visually examine the graph we need to check greater percentage change between -

Day 2 to Day 3 VS Day 4 to Day 5

Percentage change in Day 2 to Day 3= 50%
Percentage change in Day 4 to Day 5 = 60%

Thus, the correct answer will be (D)
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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04 Jul 2017, 14:18
1
1
AbdurRakib wrote:

The graph shows the number of computers assembled during each of 6 consecutive days.From what day to the next day was the percent change in the number of computers assembled the greatest in magnitude ?

A. From Day 1 to Day 2
B. From Day 2 to Day 3
C. From Day 3 to Day 4
D. From Day 4 to Day 5
E. From Day 5 to Day 6

Attachment:
zxwlzd.jpg

Used a visual scan technique.
1. In cases where value drop from previous day, % change is going to be -ve so ignoring them. E.g. Day 1 to 2.
2. we have only 2 candidates, Day 2 to 3 and Day 4 to 5., Visual observation says both have same increment over previous day.
But Day 4 to 5 has changed value on a smaller denominator then the Day 2 to 3 ...so it wins.
if someone is not from data analytics field then better calculate to verify.
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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11 Nov 2017, 16:57
1
dangeyg wrote:
AbdurRakib wrote:

The graph shows the number of computers assembled during each of 6 consecutive days.From what day to the next day was the percent change in the number of computers assembled the greatest in magnitude ?

A. From Day 1 to Day 2
B. From Day 2 to Day 3
C. From Day 3 to Day 4
D. From Day 4 to Day 5
E. From Day 5 to Day 6

Attachment:
zxwlzd.jpg

Used a visual scan technique.
1. In cases where value drop from previous day, % change is going to be -ve so ignoring them. E.g. Day 1 to 2.
2. we have only 2 candidates, Day 2 to 3 and Day 4 to 5., Visual observation says both have same increment over previous day.
But Day 4 to 5 has changed value on a smaller denominator then the Day 2 to 3 ...so it wins.
if someone is not from data analytics field then better calculate to verify.

You need to be a little careful here. The question states - percent change in the number of computers assembled has the greatest in magnitude. So your 1st point could get you into trouble but not in this question though!
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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15 Nov 2017, 17:19
2
AbdurRakib wrote:

The graph shows the number of computers assembled during each of 6 consecutive days.From what day to the next day was the percent change in the number of computers assembled the greatest in magnitude ?

A. From Day 1 to Day 2
B. From Day 2 to Day 3
C. From Day 3 to Day 4
D. From Day 4 to Day 5
E. From Day 5 to Day 6

Attachment:
zxwlzd.jpg

A) From Day 1 to Day 2

|(12 - 20)/20| x 100 = |-8/20| x 100 = 40%

B) From Day 2 to Day 3

[(18 - 12)/12] x 100 = |6/12| x 100 = 50%

C) From Day 3 to Day 4

|(10 - 18)/18| x 100 = |-8/18| x 100 = 44.44%

D) From Day 4 to Day 5

[(16 - 10)/10] x 100 = |6/10| x 100 = 60%

E) From Day 5 to Day 6

|(8 - 16)/16| x 100 = |-8/16| x 100 = 50%

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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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17 Nov 2017, 04:28
1
Change is percentage can be calculated by understanding the fractional change in the numbers. (if number changes from 6 to 8, then fractional change is |6-8|/6). The denominator will be the first/initial number and the numerator will be the difference between the two numbers. (As magnitude has been asked, negative or positive will not affect the answer).
In this problem, we get following results of subtraction:
1. 8/20
2. 6/12
3. 8/18
4. 6/10
5. 8/16
Options 1 and 3 are eliminated as they are less than option 5 (Same numerator, different denominator)
Option 2 and Option 5 are same (1/2) hence both eliminated. Option 4 remains, and hence the answer.

Observing the number might not give the solution this easily every time but it helps to sit back and think about the numbers for 2-5 seconds.
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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20 Nov 2017, 17:28
Hi All,

We're given a graph that shows the number of computers assembled on each of 6 consecutive days. We're asked for the day-to-the-next-day pair that had the GREATEST PERCENT CHANGE in the number of computers assembled. To answer this question, we'll need the Percent Change Formula (and a little math):

Percent Change = (New - Old)/Old = Difference/Original

Day 1-2: 8/20 = 4/10 = 40%
Day 2-3: 6/12 = 1/2 = 50%
Day 3-4: 8/18 = 4/9 = 44.4444%
Day 4-5: 6/10 = 60%
Day 5-6: 8/16 = 1/2 = 50%

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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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18 Mar 2018, 08:37
sachinpoovanna

Quote:
Used a visual scan technique.
1. In cases where value drop from previous day, % change is going to be -ve so ignoring them. E.g. Day 1 to 2.
2. we have only 2 candidates, Day 2 to 3 and Day 4 to 5., Visual observation says both have same increment over previous day.
But Day 4 to 5 has changed value on a smaller denominator then the Day 2 to 3 ...so it wins.
if someone is not from data analytics field then better calculate to verify.

Quote:
You need to be a little careful here. The question states - percent change in the number of computers assembled has the greatest in magnitude. So your 1st point could get you into trouble but not in this question though!

Can you elaborate your point? We do not care about positive or negative change, just change of magnitude here. Much as a modulus.
What is incorrect about highlighted text?

niks18 chetan2u Bunuel
Can I not simply look at the bar graph difference ignoring the denominator (earlier value) here? Is there any
efficient way than to calculate step by step % changes for each option ?
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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18 Mar 2018, 08:57
3
sachinpoovanna

Quote:
Used a visual scan technique.
1. In cases where value drop from previous day, % change is going to be -ve so ignoring them. E.g. Day 1 to 2.
2. we have only 2 candidates, Day 2 to 3 and Day 4 to 5., Visual observation says both have same increment over previous day.
But Day 4 to 5 has changed value on a smaller denominator then the Day 2 to 3 ...so it wins.
if someone is not from data analytics field then better calculate to verify.

Quote:
You need to be a little careful here. The question states - percent change in the number of computers assembled has the greatest in magnitude. So your 1st point could get you into trouble but not in this question though!

Can you elaborate your point? We do not care about positive or negative change, just change of magnitude here. Much as a modulus.
What is incorrect about highlighted text?

niks18 chetan2u Bunuel
Can I not simply look at the bar graph difference ignoring the denominator (earlier value) here? Is there any
efficient way than to calculate step by step % changes for each option ?

Hi...

1) first point about change in %..
You are correct , it has to be taken for all choices. Increase/ decrease does not matter..
The member has been lucky to get away with this flaw and get Correct answer.

2) Do you have to go for each choice..
NO

Just look at the down ones.. 1-2, 3-4, 5-6..
Each day the drop is 4 boxes...
So 4 boxes on the least boxes previous day will win..
Nothing but we have same numerator and we are looking for SMALLEST denominator.. visually the lowest is on 5 day so % on that day = 4/8 *100=50%
Now look for the same in increasing days...increase is of 3 boxes..
On 4-5 day it is lowest so 3/5*100=60%
Our Ans
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Re: The graph shows the number of computers assembled during each of 6 con  [#permalink]

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29 Jun 2019, 21:45
The question asked for "greatest in magnitude" so we have to find the percentage change that has the highest absolute value.

I used visual reasoning for this one.

1) Look at the absolute change.
Decreasing: Day 1->2; 3->4; 5->6 has the same absolute change of 8
Increasing: Day 2->3; 4->5 has the same absolute change of 6

2) The highest magnitude will be the one with the lowest denominator
Decreasing: Day 5 is the lowest among this group so keep Day 5->6
Increasing: Day 4 is the lowest among this group so keep Day 4->5

3) Calculate only the two candidates
Decreasing: 8/16 = 50%
Increasing: 6/10 = 60%

With this, the question can be done in about 1 min
Re: The graph shows the number of computers assembled during each of 6 con   [#permalink] 29 Jun 2019, 21:45
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