GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 19 Dec 2018, 03:42

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in December
PrevNext
SuMoTuWeThFrSa
2526272829301
2345678
9101112131415
16171819202122
23242526272829
303112345
Open Detailed Calendar
  • Happy Christmas 20% Sale! Math Revolution All-In-One Products!

     December 20, 2018

     December 20, 2018

     10:00 PM PST

     11:00 PM PST

    This is the most inexpensive and attractive price in the market. Get the course now!
  • Key Strategies to Master GMAT SC

     December 22, 2018

     December 22, 2018

     07:00 AM PST

     09:00 AM PST

    Attend this webinar to learn how to leverage Meaning and Logic to solve the most challenging Sentence Correction Questions.

The greatest possible (straight line) distance, in inches, between any

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 51302
The greatest possible (straight line) distance, in inches, between any  [#permalink]

Show Tags

New post 07 Oct 2016, 01:33
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

64% (02:29) correct 36% (02:44) wrong based on 125 sessions

HideShow timer Statistics

The greatest possible (straight line) distance, in inches, between any two points on a certain cube is 10. If the cube is modified so that its length is doubled and its width is doubled while its height remains unchanged, then what is the greatest possible (straight line) distance, in inches, between any two points on the modified box?

A. 10√2
B. 10√3
C. 20
D. 30
E. 30√3

_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Senior PS Moderator
User avatar
V
Joined: 26 Feb 2016
Posts: 3327
Location: India
GPA: 3.12
Premium Member CAT Tests
The greatest possible (straight line) distance, in inches, between any  [#permalink]

Show Tags

New post 07 Oct 2016, 04:35
1
1
The greatest distance(straight line) between two points in a cube is its diagonal.
Here the length of the digaonal is 10.
Therefore, Side*\(\sqrt{3} = 10\)
Side = \(\frac{10}{\sqrt{3}}\)

Since the length and breadth doubles, and height remains the same.
The new box is a cuboid with length = breadth = \(\frac{20}{\sqrt{3}}\) and height is \(\frac{10}{\sqrt{3}}\)

The straight line greatest distance is the diagonal.
Diagonal = \(\sqrt{length^2 + breadth^2 + height^2} = \sqrt{300} = 10*\sqrt{3}\)(Option B)
_________________

You've got what it takes, but it will take everything you've got

Intern
Intern
avatar
B
Joined: 06 Oct 2017
Posts: 30
Re: The greatest possible (straight line) distance, in inches, between any  [#permalink]

Show Tags

New post 19 Feb 2018, 16:55
pushpitkc wrote:
The greatest distance(straight line) between two points in a cube is its diagonal.
Here the length of the digaonal is 10.
Therefore, Side*\(\sqrt{3} = 10\)
Side = \(\frac{10}{\sqrt{3}}\)

Since the length and breadth doubles, and height remains the same.
The new box is a cuboid with length = breadth = \(\frac{20}{\sqrt{3}}\) and height is \(\frac{10}{\sqrt{3}}\)

The straight line greatest distance is the diagonal.
Diagonal = \(\sqrt{length^2 + breadth^2 + height^2} = \sqrt{300} = 10*\sqrt{3}\)(Option B)


Can you please explain how you got the square root of 300? I am so lost at that point?
Senior PS Moderator
User avatar
V
Joined: 26 Feb 2016
Posts: 3327
Location: India
GPA: 3.12
Premium Member CAT Tests
Re: The greatest possible (straight line) distance, in inches, between any  [#permalink]

Show Tags

New post 19 Feb 2018, 18:32
300 is 10*10*3 or \(3 * 10^2\)

The square root of 300 is 10*sqft(3) as 10 comes outside the square

Hope that helps!
_________________

You've got what it takes, but it will take everything you've got

Intern
Intern
avatar
B
Joined: 06 Oct 2017
Posts: 30
The greatest possible (straight line) distance, in inches, between any  [#permalink]

Show Tags

New post 19 Feb 2018, 18:35
pushpitkc wrote:
300 is 10*10*3 or \(3 * 10^2\)

The square root of 300 is 10*sqft(3) as 10 comes outside the square

Hope that helps!


But if the new box is a cuboid with length = breadth = 20/√3 and height is 10/√3 then where are the 10*10*3 coming from? Shountld you be multiplying the two 20/√3 with the 10/√3 ?

Sorry but for some reason this is literally going over my head....
Math Expert
User avatar
V
Joined: 02 Aug 2009
Posts: 7113
Re: The greatest possible (straight line) distance, in inches, between any  [#permalink]

Show Tags

New post 19 Feb 2018, 19:15
1
aanjumz92 wrote:
pushpitkc wrote:
300 is 10*10*3 or \(3 * 10^2\)

The square root of 300 is 10*sqft(3) as 10 comes outside the square

Hope that helps!


But if the new box is a cuboid with length = breadth = 20/√3 and height is 10/√3 then where are the 10*10*3 coming from? Shountld you be multiplying the two 20/√3 with the 10/√3 ?

Sorry but for some reason this is literally going over my head....


Diagonal = \(\sqrt{length^2 + breadth^2 + height^2} = \sqrt{(\frac{20}{sqroot3})^2 + (\frac{20}{sqroot3})^2 + (\frac{10}{sqroot3})^2}= \sqrt{(\frac{400}{3}) + (\frac{400}{3}) + (\frac{100}{3})}= \sqrt{\frac{900}{3} =}
\sqrt{300} = 10*\sqrt{3}\)(Option B)
_________________

1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html


GMAT online Tutor

Veritas Prep GMAT Instructor
User avatar
P
Joined: 16 Oct 2010
Posts: 8690
Location: Pune, India
The greatest possible (straight line) distance, in inches, between any  [#permalink]

Show Tags

New post 19 Feb 2018, 21:54
Bunuel wrote:
The greatest possible (straight line) distance, in inches, between any two points on a certain cube is 10. If the cube is modified so that its length is doubled and its width is doubled while its height remains unchanged, then what is the greatest possible (straight line) distance, in inches, between any two points on the modified box?

A. 10√2
B. 10√3
C. 20
D. 30
E. 30√3

Attachment:
Unknown.png
Unknown.png [ 1.69 KiB | Viewed 433 times ]

The greatest possible distance between any two points on a cube is the diagonal (D) which is also the hypotenuse of the triangle made by the the shorter diagonal (d) and a. The shorter diagonal (d) is the hypotenuse of sides a and a.
So \(d^2 = a^2 + a^2\)
and \(D^2 = d^2 + a^2 = 3a^2\)
\(D = \sqrt{3}a = 10\)

If length and width are doubled, New \(d^2 = (2a)^2 + (2a)^2 = 8a^2\)
New \(D^2 = 8a^2 + a^2 = 9a^2\)
Then New \(D = 3a = 10\sqrt{3}\)

Answer (B)
_________________

Karishma
Veritas Prep GMAT Instructor

Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >

GMAT Club Bot
The greatest possible (straight line) distance, in inches, between any &nbs [#permalink] 19 Feb 2018, 21:54
Display posts from previous: Sort by

The greatest possible (straight line) distance, in inches, between any

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.