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The integer x is even and the integer y is odd. Is the integer z odd?

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Bunuel
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The integer x is even and the integer y is odd. Is the integer z odd? [#permalink] New post   20 Dec 2018, 02:25
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A
B
C
D
E

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15% (low)

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78% (01:25) correct 22% (01:39) wrong based on 139 sessions
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The integer x is even and the integer y is odd. Is the integer z odd?


(1) xyz+ 1 is odd.

(2) xy + xz + yz is even.
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B
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Ypsychotic
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Re: The integer x is even and the integer y is odd. Is the integer z odd? [#permalink] New post   20 Dec 2018, 03:51
Bunuel wrote:
The integer x is even and the integer y is odd. Is the integer z odd?


(1) xyz+ 1 is odd.

(2) xy + xz + yz is even.


x is even & y is odd.

1) xyz+1=odd. xy is even, z can be either even or odd. Insufficient.

2) xy=even, xz=even, as x is even. hence, yz is even. As Even + Even + x is even, So, x is even.
Since y is odd, so z is even. Z isn't odd. Sufficient.

IMO, Option B.
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Re: The integer x is even and the integer y is odd. Is the integer z odd? [#permalink] New post   20 Dec 2018, 04:23
Bunuel wrote:
The integer x is even and the integer y is odd. Is the integer z odd?


(1) xyz+ 1 is odd.

(2) xy + xz + yz is even.



Note : x = even. y=odd.

Statement 1; xyz + 1 = odd. xyz=even as x is even. it's not possible to identify specifically whether z is odd or even. NOT sufficient.

Statement 2. xy =even. xz =even. y =odd. So, z has to be an even integer in order to make the statement true. Sufficient. z =even.

The correct answer is B.
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Re: The integer x is even and the integer y is odd. Is the integer z odd? [#permalink] New post   08 Oct 2019, 00:55
Bunuel wrote:
The integer x is even and the integer y is odd. Is the integer z odd?


(1) xyz+ 1 is odd.

(2) xy + xz + yz is even.


even = e, odd = o

e.e = e e+e=e
e.o=e e+o=o
o.o =o o+o=e

use this and its easy
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Re: The integer x is even and the integer y is odd. Is the integer z odd? [#permalink]
08 Oct 2019, 00:55
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Bunuel
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