Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 25 May 2017, 07:32

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# The integers m and p are such that 2<m<p and m is not

Author Message
Director
Joined: 01 May 2007
Posts: 793
Followers: 2

Kudos [?]: 330 [0], given: 0

The integers m and p are such that 2<m<p and m is not [#permalink]

### Show Tags

28 Feb 2008, 09:10
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The integers m and p are such that 2<m<p and m is not a factor of p. If r is the remainder when p is divided by m, is r>1?

(1)The greatest common factor of m and p is 2.
(2) The least common multiple of m and p is 30.
CEO
Joined: 29 Mar 2007
Posts: 2562
Followers: 21

Kudos [?]: 453 [0], given: 0

### Show Tags

28 Feb 2008, 09:15
jimmyjamesdonkey wrote:
The integers m and p are such that 2<m<p and m is not a factor of p. If r is the remainder when p is divided by m, is r>1?

(1)The greatest common factor of m and p is 2.
(2) The least common multiple of m and p is 30.

1: seems to be suff. b/c both m and p must be even. and 2<m<p thus we can only have something like 6<8 8<10 etc...

thus r>1

2: 2<10<15 or 2<5<6. 15/10 r>1. 6/5 r=1 Insuff.

A
Director
Joined: 01 May 2007
Posts: 793
Followers: 2

Kudos [?]: 330 [0], given: 0

### Show Tags

28 Feb 2008, 09:28
GMATBLACKBELT, The OA is A...and I had the same reasoning...but...

what about 2 < 4 < 8?

That doesn't work 8/4 = r0? What am I missing here?
Director
Joined: 01 May 2007
Posts: 793
Followers: 2

Kudos [?]: 330 [0], given: 0

### Show Tags

28 Feb 2008, 09:28
Doh, nevermind...It's because m is not a factor of p correct?
Director
Joined: 01 May 2007
Posts: 793
Followers: 2

Kudos [?]: 330 [0], given: 0

### Show Tags

28 Feb 2008, 12:56
Can someone explain how (2) The least common multiple of m and p is 30. is not suff?

I know it isn't...but would like to see how it is calculated. Thanks.
VP
Joined: 22 Oct 2006
Posts: 1438
Schools: Chicago Booth '11
Followers: 9

Kudos [?]: 192 [0], given: 12

### Show Tags

28 Feb 2008, 16:43
I just picked numbers 6/5 has a remainder 1 and a LCM of 30

then I tried to figure other numbers I was like 6*10 30 is LCM 10/6 R of 4
Re: GMATprep problem   [#permalink] 28 Feb 2008, 16:43
Display posts from previous: Sort by