Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

21 - 1 alone.
Area of a parallellogram is base x height
So area cannot be greater than 42 as height cannot be greater than either 6 or 7.
_________________

For the same measures of length and width, area of rectangle is always larger than the area of parallelogram ( since the length of hypotenuse is always larger than the length of the leg).

In this case, if the figure was a rectangle, area would be equal to 6*7=42

21 - 1 alone. Area of a parallellogram is base x height So area cannot be greater than 42 as height cannot be greater than either 6 or 7.

Folks I just dont understand how can the area of the llgm be 21.

Please explain.

hkm_gmat, at first I was also confused.

I think that the question asks what are the possible values "among the floowing".

Assuming 7 as the base, if we calculate the largest possible area, it would come out to 7*6 = 42.

Infact the area of the parallelogram would be such that:
0 < Area of ll of gram <= 42

So (III) 84 is out. The other two values 21 & 42 are possible.
_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

Wouldnt it be exact 42... when the 2 sides of a parallaleogram are given then how can the area have a minimum and a max value??

Andy, the angle between the sides of the parallelogram is not given. Depending on the angle, you would get different heights and hence different areas.
_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."