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The number of molecules of carbon dioxide used in an experiment was originally \(10^3\). During the next 2 hours, the number of molecules of carbon tripled every 15 minutes. What was the number of molecules 2 hours later?
(A) \(3(10^3)\)
(B) \(27(10^3)\)
(C) \((10^8)(10^3)\)
(D) \((3^8)(10^3)\)
(E) \((10^3)^8\)
(A) \(3(10^3)\)
(B) \(27(10^3)\)
(C) \((10^8)(10^3)\)
(D) \((3^8)(10^3)\)
(E) \((10^3)^8\)
04 Jul 2022, 05:31
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The total duration of tripling is 2 hours.
Since it is tripling every 15 minutes, it will increase 120/15 = 8 times.
As the initial number is 10^3, the final number of molecules will be (10^3)*3^8.
Thus, the correct option is D.
Since it is tripling every 15 minutes, it will increase 120/15 = 8 times.
As the initial number is 10^3, the final number of molecules will be (10^3)*3^8.
Thus, the correct option is D.
