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# The number of passengers on a certain bus at any given time

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Director
Joined: 23 May 2008
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The number of passengers on a certain bus at any given time [#permalink]

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13 Sep 2008, 16:41
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0
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Director
Joined: 23 Sep 2007
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13 Sep 2008, 16:49
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0

The correct formula is P = -2(S – 4)^2 + 32

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Director
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13 Sep 2008, 16:54
C

the max number of passenger is at the 4th stop, at the 6th stop, there will be 24

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Manager
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13 Sep 2008, 17:01
If by 2(S – 4)2 + 32 you mean 2(S – 4)^2 + 32 .. then yes after 6 stops , the number of passenger will be 24

IMO C .

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Senior Manager
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13 Sep 2008, 17:14
(C) for me too.

Based on the formula, highest # of passenger is when s=4, i.e P=32.
2 stops after when s=4 is -> s=6. P=24 when S=6 and hence (C)
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Director
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13 Sep 2008, 18:00
OA is C, sorry about the typo

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VP
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13 Sep 2008, 23:45
gmatnub wrote:
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0

The correct formula is P = -2(S – 4)^2 + 32

IMO C
4th stop max=32 ,
6th stop => 24 => IMO C
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SVP
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15 Sep 2008, 00:42
gmatnub wrote:
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0

The correct formula is P = -2(S – 4)^2 + 32

That made sense. Otherwise, with S = 0, P was not coming out to 0.

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Re: another mgmat   [#permalink] 15 Sep 2008, 00:42
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# The number of passengers on a certain bus at any given time

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