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# The number of stamps Jim and John had were in the ratio of

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Intern
Joined: 13 Jan 2008
Posts: 24
The number of stamps Jim and John had were in the ratio of [#permalink]

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23 Jan 2008, 14:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The number of stamps Jim and John had were in the ratio of 5:3 respectively. After Jim gave John 10 of his stamps, the ratio of the numer Jim had to the number John had was 7:5. As a result of the gift, Jim ahd how many more than John?

20
30
40
60
90
Senior Manager
Joined: 22 Sep 2005
Posts: 276

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23 Jan 2008, 15:13

We have 2 eq with 2 variables. We only need to solve it:

1) Jim/John = 3/5. We have Jim=3/5 John

2) (Jim-10)/ (John+10)=7/5

If we isolate John, we have John=90, so Jim =150

Later Jim=140 and John =100, so the answer is 40
Intern
Joined: 03 Jan 2008
Posts: 7

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23 Jan 2008, 15:31
Yes C.
If x & y are the stamps Jim and John have.

So, we have 2 eqns,
x/y = 5/3 &
x-10/y+10 = 7/5

Solving:
we get y=90 & x = 150.

So, after Jim gives John 10 stamps, it is: x=140, y=100. So, 40 stamps. C
Re: Ratio   [#permalink] 23 Jan 2008, 15:31
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# The number of stamps Jim and John had were in the ratio of

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