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THe # of stamps that Kim and Andy had were in the ration

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THe # of stamps that Kim and Andy had were in the ration [#permalink]

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New post 10 Oct 2005, 07:07
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

THe # of stamps that Kim and Andy had were in the ration 5:3. After Kim gave 10 stamps to Andy, the ration was 7:5.
as a restult of the gift, kim had how mnay more stamps than Andy?
a. 20
b. 30
c. 40
d. 60
e. 90

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Re: Ratio question- how do u do it? [#permalink]

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New post 10 Oct 2005, 07:20
Jennif102 wrote:
THe # of stamps that Kim and Andy had were in the ration 5:3. After Kim gave 10 stamps to Andy, the ration was 7:5.
as a restult of the gift, kim had how mnay more stamps than Andy?
a. 20
b. 30
c. 40
d. 60
e. 90


let x and y be the stamps of K and A respectively
x:y=5:3---->x=5/3y
(x-10): (y+10)=7:5---->5x-50=7y+70
substitue x by y ,we have : 25/3y-50=7y+70<===> y=90 --->
x=5/3(90)=150
---->x-y=60
D.

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I got C [#permalink]

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New post 10 Oct 2005, 07:34
C. 40. laxieqv. Your math is correct, but the answer is looking for what the difference between Kim and Andy is AFTER the gift. Your answer is provides the difference before the gift.
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New post 10 Oct 2005, 07:46
Agree w/ Chris. I got (c), Laxie #'s were before the gift.

B.

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New post 10 Oct 2005, 07:53
I was just reading Peterson's the other day and trying to use plugging in to arrive at the answer. And was getting nowhere very fast.

How'd you do it by plugging in?

(Plugging in seems a little unnatural to me - the equation method would work for me.)

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New post 10 Oct 2005, 08:03
oops, I was too careless as reading the question :oops:

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New post 15 Oct 2005, 10:02
am still lost...

what i went about is
5 /8 (x-10) = 7 /12 (x)
x = 150
2/12 (150) = 25 ( 2 is the diff 7-5 to for the 2nd ratio)

pls i need a simple explanation :?: as 40 is the OA
thks

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New post 15 Oct 2005, 10:08
K/A=5/3

(K-10)/(A+10)=7/5

now solve for K and A...

once you get K and A, then you minus K-A to get the difference...

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New post 15 Oct 2005, 10:16
sushom101:

Hope you are clear on this part.

Quote:
let x and y be the stamps of K and A respectively
x:y=5:3---->x=5/3y
(x-10): (y+10)=7:5---->5x-50=7y+70
substitue x by y ,we have : 25/3y-50=7y+70<===> y=90 --->
x=5/3(90)=150
---->x-y=60


We have found x and y. Now kim gave 10 stamps to andy. So the new x = 140 and new y = 100. The difference is 40.

Hope it is clear now.

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New post 15 Oct 2005, 10:16
I had the exact same type of question on the official test last month, and probably missed it!

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New post 15 Oct 2005, 10:40
hey! got it guys...thanks

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New post 15 Oct 2005, 13:07
Assume the number of stamps = n

Initially:
K = 5n/8 stamps
A = 3n/8 stamps

k gave 10 stamps to Andy --> 5n/8 - 10
A got 10 stamps from Kim --> 3n/8 + 10

The new ratio (Kim:Andy) = 7/5 = (5n/8-10)/(3n/8+10)

Solving -> n = 240

Kim now has 7/12 * 240 = 140 stamps
Andy now has 240-140 = 100 stamps

So Kim has 140-100 = 40 stamps more than Andy.

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  [#permalink] 15 Oct 2005, 13:07
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THe # of stamps that Kim and Andy had were in the ration

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