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The percent of employees participated in A program is 80% of the total

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The percent of employees participated in A program is 80% of the total [#permalink]

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New post 08 Aug 2017, 18:09
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The percent of employees participated in A program is 80% of the total employees. What is the total number of employees in the company?

1) 168 employees participated in this program.
2) 42 employees did not participate in this program.
[Reveal] Spoiler: OA

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Re: The percent of employees participated in A program is 80% of the total [#permalink]

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New post 08 Aug 2017, 21:31
Stmnt 1
0.8* total no = 168

Stmnt 2
80% Participated so (100-80)=20% not participated

Hence 0.2 * total no = 42

Both stmnt independently give you total no of employees

Hence ans should be D

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Re: The percent of employees participated in A program is 80% of the total [#permalink]

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New post 08 Aug 2017, 23:32
MathRevolution wrote:
The percent of employees participated in A program is 80% of the total employees. What is the total number of employees in the company?

1) 168 employees participated in this program.
2) 42 employees did not participate in this program.


Let total number of employees in \(A\) program be \(= x\)

Given \(80\)% of total employees participated in \(A\) program.

1) \(168\) employees participated in this program.

\(80\)% of \(x = 168 => \frac{80}{100}* x = 168\)

\(x = \frac{168 * 100}{80} = 210\)

Therefore, Total number of employees in \(A\) program \(= 210\)

Hence I is Sufficient.

2) \(42\) employees did not participate in this program.

Given \(80\)% of total employees participated in \(A\) program. Therefore \(20\)% of total employees did not participate in \(A\) program.

Therefore; \(20\)% of \(x = 42 => \frac{20}{100} * x = 42\)

\(x = \frac{42* 100}{20} = 210\)

Therefore, Total number of employees in \(A\) program \(= 210\)

Hence II is Sufficient.

Answer (D)...

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Re: The percent of employees participated in A program is 80% of the total [#permalink]

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New post 10 Aug 2017, 01:12
==> If you modify the original condition and the question and set the number of people who participated in the program as a and number of people who did not participate in the program as b, from a=80%(a+b), there are 2 variables and 1 equation. Since there is 1 for con 1) and 1 for con 2), D is most likely to be the answer.

For con 1), from 168=80%(a+b) and a+b=168/80%=210, it is unique and sufficient.
For con 2), from 42=20%(a+b) and a+b=42/20%=210, it is unique and sufficient.

Therefore, the answer is D.
Answer: D
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Re: The percent of employees participated in A program is 80% of the total [#permalink]

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New post 10 Aug 2017, 11:49
MathRevolution wrote:
The percent of employees participated in A program is 80% of the total employees. What is the total number of employees in the company?

1) 168 employees participated in this program.
2) 42 employees did not participate in this program.


Total Employees = T
Emp's in Pgm A = 0.8T
T = ?

1) 168 = 0.8T
=> T = 210
Sufficient.

2) 42 did NOT participate
0.8T + 42 = T
=> 0.2T = 42
=> T = 210
Sufficient.

Answer is D
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Re: The percent of employees participated in A program is 80% of the total   [#permalink] 10 Aug 2017, 11:49
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