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Re: The points (0,3) and (4,0) are joined to find a triangle with x-axis a [#permalink]
area of ∆ ; 1/2 * 3*4 ; 6
and area of circle ; 25 * 3.14 ; ~ 78.5
% of area of ∆ covering circle ; 6/78.5 * 100 = 8%
IMO B


Bunuel wrote:
The points (0,3) and (4,0) are joined to find a triangle with x-axis and y-axis as the other sides of the triangle. The area of this triangle overlaps with approximately what percentage of the area of a circle with equation x^2 + y^2 = 25 ?

A. 4%
B. 8%
C. 12%
D. 16%
E. 20%

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The points (0,3) and (4,0) are joined to find a triangle with x-axis a [#permalink]
Given:
- Points (0,3) and (4,0) are joined to find a triangle with x-axis and y-axis
We get triangle with base 4 and height 3.
- Equation: x^2 + y^2 = 25
We get radius = 25

- Area of triangle = 1/2*4*3 = 6
- Area of Circle = 25π

Percent of triangle are in circle = 6 of 25π =~ 8%

Option B
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Re: The points (0,3) and (4,0) are joined to find a triangle with x-axis a [#permalink]
Bunuel wrote:
The points (0,3) and (4,0) are joined to find a triangle with x-axis and y-axis as the other sides of the triangle. The area of this triangle overlaps with approximately what percentage of the area of a circle with equation x^2 + y^2 = 25 ?

A. 4%
B. 8%
C. 12%
D. 16%
E. 20%


circle with x^2 + y^2 = 25 has r^2=25, r=5, area=25π
triangle (0,3)(4,0) x and y axis, has area=3*4/2=6
area(t/c)=6/25π~6/5^2*22/7~21/25*11~21/275
5%275<21<10%275=8%

Ans (B)
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Re: The points (0,3) and (4,0) are joined to find a triangle with x-axis a [#permalink]
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Re: The points (0,3) and (4,0) are joined to find a triangle with x-axis a [#permalink]
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