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The price of car A increased by 20 percent over the same time period

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The price of car A increased by 20 percent over the same time period [#permalink]

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New post 28 Mar 2010, 16:28
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The price of car A increased by 20 percent over the same time period that the price of car B decreased by 20 percent. The reduced price of car B was what percent of the original price of car A?

(1) The increased price of car A is equal to the original price of car B.
(2) The increase in price of car A was 5/6 the decrease in the price of car B.
[Reveal] Spoiler: OA

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Re: The price of car A increased by 20 percent over the same time period [#permalink]

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New post 28 Mar 2010, 18:01
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If a and b are the original prices of car A and car B respectively
After the change their prices will be 1.2a and 0.8b
We need to find what percent of car A original price is the reduced price of car B i.e 0.8b/a *100

As per 1 increase price of car A is equal to the original price of car B i.e 1.2a=b from which we can calculate b/a and the required percentage so 1 alone is sufficient
As per 2 increase in price of car A was 5/6 the decrease in the price of car B i.e 0.2a = 5/6*(0.2b) from which we can calculate b/a and the required percentage so 2 alone is sufficient.

Answer should be D
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Re: The price of car A increased by 20 percent over the same time period [#permalink]

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New post 29 Mar 2010, 02:43
First thought answer is A but agree with the explanation given by Crack700

Thanks crack for your explanation
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Re: The price of car A increased by 20 percent over the same time period [#permalink]

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New post 29 Mar 2010, 12:33
crack700 wrote:
If a and b are the original prices of car A and car B respectively
After the change their prices will be 1.2a and 0.8b
We need to find what percent of car A original price is the reduced price of car B i.e 0.8b/a *100

As per 1 increase price of car A is equal to the original price of car B i.e 1.2a=b from which we can calculate b/a and the required percentage so 1 alone is sufficient
As per 2 increase in price of car A was 5/6 the decrease in the price of car B i.e 0.2a = 5/6*(0.2b) from which we can calculate b/a and the required percentage so 2 alone is sufficient.

Answer should be D


Good explanation . Answer would be D

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Re: The price of car A increased by 20 percent over the same time period [#permalink]

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New post 20 Jul 2017, 23:39
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Re: The price of car A increased by 20 percent over the same time period [#permalink]

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New post 21 Jul 2017, 01:40
nsp007 wrote:
The price of car A increased by 20 percent over the same time period that the price of car B decreased by 20 percent. The reduced price of car B was what percent of the original price of car A?

(1) The increased price of car A is equal to the original price of car B.
(2) The increase in price of car A was 5/6 the decrease in the price of car B.


Car A = $ x
Car B = $ y

New Car A Price = $1.2x
New Car B Price = $0.8y

z = \(\frac{(0.8y*100)}{x}\)
z = ?

1) 1.2x = y
\(\frac{y}{x}\) = 1.2
Put this in z = \(\frac{(0.8y*100)}{x}\) and we get the value of z.
z = 96%
Sufficient.

2) 0.2x = \(\frac{5}{6}\)*0.2y
\(\frac{y}{x}\) = \(\frac{6}{5}\)
Put this in z = \(\frac{(0.8y*100)}{x}\) and we get the value of z.
z = 96%
Sufficient.

D is the answer.
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Re: The price of car A increased by 20 percent over the same time period   [#permalink] 21 Jul 2017, 01:40
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