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# The probability of pulling a black ball out of a glass jar

Author Message
Director
Joined: 22 Aug 2007
Posts: 566

Kudos [?]: 71 [0], given: 0

The probability of pulling a black ball out of a glass jar [#permalink]

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22 Sep 2007, 09:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).

Kudos [?]: 71 [0], given: 0

VP
Joined: 10 Jun 2007
Posts: 1434

Kudos [?]: 350 [0], given: 0

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22 Sep 2007, 09:55
IrinaOK wrote:
The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).

I got b
P(black)=1/x
P(break and black)=1/y=P(black)xP(break)
P(break)= x/y

Kudos [?]: 350 [0], given: 0

Director
Joined: 11 Jun 2007
Posts: 910

Kudos [?]: 278 [0], given: 0

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22 Sep 2007, 09:57
IrinaOK wrote:
The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).

A = probability of pulling a black ball out of a glass jar 1/X
B = probability of breaking the jar
C = pulling a black ball out of a glass jar and breaking the jar 1/Y

A * B = C

solve for B: B = C / A
B = (1/Y) / (1/X)
B = X /Y (answer B)

Kudos [?]: 278 [0], given: 0

Current Student
Joined: 28 Dec 2004
Posts: 3351

Kudos [?]: 319 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

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22 Sep 2007, 10:05
i got B too...

prob of pulling ball 1/x

prob of breaking jar 1/n

prob of pulling ball AND breaking jar 1/y

1/x * 1/n =1/y

1/n=x/y

Kudos [?]: 319 [0], given: 2

22 Sep 2007, 10:05
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