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# The probability of Sam passing the exam is 1/4. The

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Senior Manager
Joined: 13 Jun 2005
Posts: 252
Location: Haverhill, MA
The probability of Sam passing the exam is 1/4. The [#permalink]

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28 Jan 2006, 09:06
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The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/6.
What is the probability of Michael passing his driving test?

a) 1/24.
b) 1/2.
c) 1/3.
d) 2/3.
e) 2/5
Manager
Joined: 15 Aug 2005
Posts: 198
Location: New York
Re: PS - one more prob. [#permalink]

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28 Jan 2006, 09:55
sperumba wrote:
The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/6.
What is the probability of Michael passing his driving test?

a) 1/24.
b) 1/2.
c) 1/3.
d) 2/3.
e) 2/5

P(S) = the probability of Sam passing the exam =1/4

P(M)= the probability of Michael passing the driving test=?

P(S) *P(M)= The probability of Sam passing the exam and Michael passing the driving test = 1/6

P(M) = (1/6)/(1/4) = 2/3
Senior Manager
Joined: 11 Nov 2005
Posts: 328
Location: London

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28 Jan 2006, 10:53
2/3

Probability of A and B = probability of A * probability of B.
Senior Manager
Joined: 13 Jun 2005
Posts: 252
Location: Haverhill, MA

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28 Jan 2006, 19:01
Indicate A as the probability of Michael passing the driving test.
The probability of Sam passing the test is 1/4, the probability of both events happening together is 1/6 so: 1/4 x A = 1/6 therefore A = 2/3.
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

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28 Jan 2006, 21:45
P(michael pass) * P(sam pass) = 1/6
P(michael pass) = (1/6)/P(sam pass)
P(michael pass) = (1/6)/1/4 = 2/3

ANs D
28 Jan 2006, 21:45
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# The probability of Sam passing the exam is 1/4. The

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